
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Cryptography:
Using the Euclidean
a) 155 37
b) 1114978 23456
c) 110010105 750
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- Simplify the following expression, 3 (-8 x –6 × 3) |4 – 12| – (6 – 4)*] 1156 3444 1148 -3468 348arrow_forwardUse A-1 to decode the cryptogram. 2 0 1 0 1 2 -9 66 27 -101 37 5 -34 61 46 -188 46 -14 9 94 21 -139 32 -4 12 66 31 -143 47 33 -162 32 19 -126 43 -9 -45 68 23 -104 A = N NH 2 -1arrow_forwardAes algorithm for symmetric cryptography a) In AES Given the plaintext (000102030405060708090A0B0CEOF) and the key (01010101010101010101010101010101) Show the original contents of State, displayed as a 4x4 matrixarrow_forward
- n = p * q = 149 * 127 = 18923 phi(n) = (p - 1) * (q - 1) = 148 * 126 = 18648 e = 1261 d = 5797 Decrypt the following using the SQUARE-AND-MULTIPLY ALGORITHM to exponentiate modulo n: 12423 11524 7243 7459 14303arrow_forwardAlice and Bob are using Elgamal to communicate with prime p = 48112959837082048697 andB = 30980566787060881636. Here’s a transcript of a recent communication.Bob: Alice, you know how much I care about you. You know I can be trusted.Won’t you tell me your phone number?Alice: I don’t want everyone at work to know. Let me encrypt it. Here you go:(17338469904166832757, 8068454082369421991).Bob: Wow, that was fast! You’re so good at encryption protocols.. . . During the interlude while Bob decrypts, Alice sends text messages to her momwith pictures of her new puppy, Woof . . .Bob: Wait, that’s your work number, 1-315-312-6586.Alice: Oh, sorry. Here’s my cell number: (41718705614960107467, 21459087071846659484).Bob: You are so quick with the encryption! How do you do that?Alice: Oh, I set the encryption program to get a new ephemeral key just by doublingthe last one. It really speeds things up compared to the default method.Edgar was listening in the whole time. Show how Edgar is able to…arrow_forward
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