Cyanamide is a compound containing two hydrogen atoms and some amount of C and N. There are a total of 5 atoms in the compound. The products of combustion were found to be CO2, NO2, and H2O. If the enthalpy of combustion for cyanamide is – 671.9 kJ/mol and the enthalpy of formation is 58.8 kJ/mol, what is the chemical formula for cyanamide? ( ΔfH (CO2) = - 393.51 kJ/mole; ΔfH (NO2) = + 33.10 kJ/mole; ΔfH (H2O) = - 241.826 kJ/mole)

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Asked Nov 2, 2019
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Cyanamide is a compound containing two hydrogen atoms and some amount of C and N. There are a total of 5 atoms in the compound. The products of combustion were found to be CO2, NO2, and H2O. If the enthalpy of combustion for cyanamide is – 671.9 kJ/mol and the enthalpy of formation is 58.8 kJ/mol, what is the chemical formula for cyanamide? ( ΔfH (CO2) = - 393.51 kJ/mole; ΔfH (NO2) = + 33.10 kJ/mole; ΔfH (H2O) = - 241.826 kJ/mole)

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From the give data, in total of 5 atoms, 2 atoms are Hydrogen, in remaining 3 atoms, let co...

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> (3-х)СО, + хNO, + H,0 CNH22 xAH NO2 +AH-ACynamide (3-х)Дн",со, Enthalpy of combustion= Н,о 671.9 kJ/mol (3-x)(-393.51kJ/mol)+x(33.10KJ/mol)+(-241.826 kJ/mol)-(58.8 kJ/mol) 809.256 426.61x 809.256 =1.9 2 X = 426.61

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