   Chapter 10, Problem 41QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
27 views

# The enthalpy change for the reaction of hydrogen gas with fluorine gas (o produce hydrogen fluoride is −542 U for the equation as written:mg src=Images/HTML_99425-10-41QAP_image001.jpg alt="" align="top"/>l type='a'>What is the enthalpy change per mole of hydrogen fluoride produced?Is the reaction exothermic or endothermic as written?What would be the enthalpy change for the reverse of the given equation (that 1%, for the decomposition of HF into its constituent elements)?

Interpretation Introduction

(a)

Interpretation:

calculate the enthalpy change for formation of hydrogen fluoride per mole.

Concept Introduction:

The enthalpy for the provided reaction is per mole.

Calculate the enthalpy based on formation of moles involved in reaction.

Explanation

To calculate the enthalpy change per mole of hydrogen fluoride produced, check the how many moles of HF is produced in provided reaction. As per the provided reaction, two moles of HF produced.

Calculate enthalpy change per mole of hydrogen fluoride produced as follows:

542kJ1<

Interpretation Introduction

(b)

Interpretation:

Understand what sign for exothermic reaction and endothermic reaction.

Concept Introduction:

In case the system absorbs heat, the process is endothermic reaction.

Incase the system evolves heat, the process is exothermic reaction.

Interpretation Introduction

(c)

Interpretation:

Check the sign change for reverse reaction.

Concept Introduction:

The enthalpy change for a reaction is equal in magnitude but opposite in sign, to the enthalpy change for the reverse reaction.

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