Describe how to prepare 15 ml of a 0.25 M CaCl2 solution using deionized water and CaCl2 salt. The molecular weight of CaCl2 is 110.98 g/mol. Show your work. (Recall: M = mol/L)
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- 1. A 50.00 mL stock CaCl2 solution was diluted with water in a 250.0-mL volumetric flask. A 25.00 mL aliquot of this was further diluted to a final volume of 100.0 mL. Finally, 20.00-mL aliquot of the resulting solution was analyzed and found to contain 0.1500 M CaCh2 Solve for the concentration of the stock solution in M. 2. A 50.00 mL stock CaCl2 solution was diluted with water in a 250.0-mL volumetric flask. A 25.00 mL aliquot of this was further diluted to a final volume of 100.0 mL. Finally, 20.00-mL aliquot of the resulting solution was analyzed and found to contain 0.1200 g CaCl2 Solve for %w/v CaCl2 in the stock solution.Show how to take 3.6E-7 mol/L AgCl and convert it to g/100 mLSolve the problems and show your solutions. a) Lambanog contains methanol (CH3OH; density of 0.792 g/mL), in which at high dosage, is lethal. If an average Filipino weighs 55.0 kg and drinks 2.00 L of lambanog, what is the highest % v/v concentration of methanol in lambanog for it to be safe if minimum lethal dose is around 0.300 g/kg of body weight?
- What volume of concentrated HCl (12.1 M) is needed to prepare 100.0 mL 0.750 M HCl? Select one: A.9.08 mL B.6.20 mL C.16.1 mL D.11.1 mLHow would you use a volumetric flask to prepare 250.0 mL of 0.150 0 M K2SO4?A student, performing the same experiment as you, recorded the following information. The original solution was diluted by a factor of 5.Calculate the volume of NaOH used to reach the equivalence point. Volume of diluted vinegar sample (mL) 25.00 Molarity of NaOH 0.0900 Initial buret reading (mL) 16.50 Final buret reading (mL) 38.00 Volume of NaOH