Determine Kc and K, at 298K for the reaction: NOBr(g) = ½ N2(g) + ½ O2(g) + ½ Br2(g) from the following information at 298 K: NO(g) = ½ N2(g) + ½ O2(g) Kc 1.55 x 1015 %3D ½ NO) + % Br2(g) = ½ NOBR(g) Kp = 2.63

Chemistry: The Molecular Science
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ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
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Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
Problem 70QRT: Use the data in Appendix J to calculate rG andKPat 25 C for the reaction 2HBr(g)+Cl2(g)2HCl(g)+Br2()...
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Determine kc and kp at 298 K
Determine Kc and K, at 298K for the reaction:
NOBr(g) = ½ N2(g) + ½ O2(g) + ½ Br2(g)
from the following information at 298 K:
NO(g) = ½ N2(g) + ½ O2(g)
Kc
1.55 x 1015
%3D
½ NO() + 4 Br2(g) = ½ NOBr(g)
Kp
= 2.63
Transcribed Image Text:Determine Kc and K, at 298K for the reaction: NOBr(g) = ½ N2(g) + ½ O2(g) + ½ Br2(g) from the following information at 298 K: NO(g) = ½ N2(g) + ½ O2(g) Kc 1.55 x 1015 %3D ½ NO() + 4 Br2(g) = ½ NOBr(g) Kp = 2.63
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