Determine the hybridization of the metal centre in the complexes below using Ligand Field Theory. 1. [RhCl3(OH)3]3- 2. [Cr(en)2(PMe3)2]

Chemistry: Principles and Practice
3rd Edition
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter19: Transitition Metals, Coordination Chemistry And Metallurgy
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Problem 19.45QE: For each d electron configuration, state the number of unpaired electrons expected in octahedral...
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Question 5 

Determine the hybridization of the metal centre in the complexes below using Ligand Field Theory.

1. [RhCl3(OH)3]3-

2. [Cr(en)2(PMe3)2]

     

Expert Solution
Step 1

Ligand field theory (LFT) describes the bonding, orbital arrangement, and other characteristics of coordination complex. It represents an application of molecular orbital theory to transition metal complexes. A transition metal ion has nine valence atomic orbital - consisting of five nd, one (n+1)s, and three (n+1)p orbitals. These orbitals are of appropriate energy to form bonding interaction with ligands. The LFT analysis is highly dependent on the geometry of the complex, but most explanations begin by describing octahedral complexes, where six ligands coordinate to the metal. Other complexes can be described by reference to crystal field theory.

Step 2

1. In [RhCl3(OH)3]3-  complex  , Rh have +3 oxidation state having d6 configuration , thus give 6 electrons. Ligands             also  contribute 12 electrons , thus 18 electrons total . Also Cl and OH are weak ligands thus no pairing occurs. So          the  hybridization of the complex is sp3d2 and orbital diagram is :

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