Determine the moisture content, the moisture content by dry weight per trial based on the table below. Description Trial 1 Trial 2 Trail 3 Trial 4 Weight of empty aluminum dish (g) 38.1151 38.1474 38.9473 38.7400 Weight of aluminum dish and soil sample (g) 90.1440 85.7554 86.6980 85.1235 Weight of aluminum dish and dry soil 67.0170 64.1915 65.1110 63.8859 Then calculate the mean, sd, and rsd of the measurements.

Determine the moisture content, the moisture content by dry weight per trial based on the table below. Description Trial 1 Trial 2 Trail 3 Trial 4 Weight of empty aluminum dish (g) 38.1151 38.1474 38.9473 38.7400 Weight of aluminum dish and soil sample (g) 90.1440 85.7554 86.6980 85.1235 Weight of aluminum dish and dry soil 67.0170 64.1915 65.1110 63.8859 Then calculate the mean, sd, and rsd of the measurements.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter17: Subsoil Exploration

Section: Chapter Questions

Problem 17.2P

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41 The data from a falling head test is shown. Diameter of standpipe: 4 cm. Initial Head: 92.9 cm. Duration of test: 12 min. Length of soil sample: 33.27 cm. Diameter of permeameter: 43 cm. If the soil permeability is 0.0028 cm/min, determine the final head (in cm.) of the permeability test. Round off to two decimal places.
Calculate % Silt using the following values; a. Weight of soil= 50 g b. HR reading at 40 sec.= 25 c. Temp at 40 sec= 25 oCd. HR at 2 hrs= 16 e. Temp at 2 hrs= 26 * A. 17.28 B. 17.25 C 17.22 D. 17.19
- Find the moisture content, using dry weight per trial based on the table. - Solve the mean, sd, and rsd of the measurements. Description Trial 1 Trial 2 Trial 3 Trial 4 Weight of empty watch glass (g) 38.1151 38.1474 38.9473 38.7400 Weight of watch glass and soil sample (g) 90.1440 85.7554 86.6980 85.1235 Weight of watch glass and dry soil 67.0170 64.1915 65.1110 63.8859
Calculate the coefficient of permeability of a soil sample of 6 cm is height and 50cm2 in cross sectional area, if the quantity of water equal to 450ml passed down in 10minutes under an effective constant head of 40cm. On oven drying, the test specimen weigh 495g. Take Gs as 2.65, calculate the seepage velocity of water during test.
Sieve # Maas retained (gr) 4 0 10 11,5 16 11,7 20 12 30 12,9 40 17,8 50 19,1 70 35,1 100 38,1 200 118 Pan 335 Draw grain size distribution curve,find D60, D30, D10 Classify the soil
You are checking a field-compacted layer of soil. The laboratory control curve has the following values: gd (kN/m3) w (%) 16.34 14 16.57 16 16.65 18 16.50 20 16.26 22 15.87 24 The specification for compaction states that the field-compacted soil must be at least 95% of the maximum control density and within of the optimum moisture for the control curve. You dig a hole 1m3 in the compacted layer and extract a sample that weighs 17.2 kN wet and 14.1 kN dry. (a) What is the compacted gd? The compaction w? The percent compaction? Does the sample meet the specifications? (b) If the specific gravity is 2.68, what is the compacted degree of saturation? If the sample were saturated at constant density, what would be the water content?
PLS ANSWER ASAPA WET OF SOIL SAMPLE HAS A VOLUME OF 4.85 x 10^-4 m3 AND WEIGHS 8.5N. AFTER OVEN DRYING, THE WEIGHT REDUCES TO 7.5N. IF sg = 2.7DETERMINE THE UNIT WEIGHT. DETERMINE THE MOISTURE CONTENT. DETERMINE THE DEGREE OF SATURATIONAnswer in 4 decimal places with unit
Subj- civil Q. An undisturbed soil sample that is cylindrical in shape and measures 3 in (76.2 mm) in diameter by 6 in (152.4 mm) in length after oven drying weighs 2.57 lb (1.166 kg bulk) as opposed to 3.04 lb (1.38 kg mass). What are the densities and the weights in (a) wet and dry units? Additionally, find out the moisture content.
A 500g (assume no wastes) of dry soil was used for a soil mechanical analysis. Themass of soil retained in each sieve, and hydrometer analysis data are given in Table 1and Table 2, respectively.Table 1. Sieve Analysis DataUS SieveDiameter Mass Ret., g2.00 mm 101.40 mm 20500 μm 135150 μm 60250 μm 145850 μm 6075 μm 45 Particle PercentDiameter Passing, %20 μm 2.510 μm 1.52 μm 11. What is the value of the percent passing for sieve with 2 mm. opening inpercentage?2.What is the value of the percent passing for sieve with 150 μm. opening inpercentage?3.What is the value of the coefficient of uniformity?4.What are the percentages of gravel, sand, and Fines using the limits indicated byUSCS?5.What are the percentages of gravel,…
identification 7 to9 7. It is the laboratory test generally used to obtain the maximum dry unit weight of compaction and the optimum moisture content. 8. The moisture content at which the maximum dry unit weight is attained generally referred to ___. 9. The weight of soil per unit volume or sometimes called the moist unit weight.
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For a falling a head permeability test, the following data were recorded. Length of soil specimen = 500 mm. Area of soil specimen = 16 cm2 Area of stand pipe = 0.97 cm2 Head difference at time t =0 is 760 mm. Head difference at time t = 6min. is 410mm. The test was conducted at a temp. of 20 ֯C. with a unit wt. of water equal to 9.789 kN/m3 and the viscosity of water at 20 ֯C is 1.005 x 10-3 N.8/m2 . Compute the hydraulic conductivity of the soil. Compute the absolute permeability of the soil. What is the head difference at time t = 4 min?

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Description	Trial 1	Trial 2	Trail 3	Trial 4
Weight of empty aluminum dish (g)	38.1151	38.1474	38.9473	38.7400
Weight of aluminum dish and soil sample (g)	90.1440	85.7554	86.6980	85.1235
Weight of aluminum dish and dry soil	67.0170	64.1915	65.1110	63.8859