Determine the number of molecules of Cr,O3 that form when 1.34 x 103 g of oxygen completely reacts according to the following equation: 4 Cr(s) + 3 02(g) → 2 Cr,03(s) STARTING AMOUNT

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Chapter5: Stoichiometry
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4:49 1
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Question 17 of 24
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Determine the number of molecules of Cr,O3
that form when 1.34 x 10³g of oxygen
completely reacts according to the following
equation:
4
Cr(s) +
O2(g) →
2
Cr,03(s)
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
2.52 x 1025
6.022 x 1023
g Cr
3.78 x 1025
4
g Cr,03
2
1.68 x 1025
g O2
1
4.24 x 103
mol Cr,O3
1.34 x 103
32.00
mol Cr
152.00
molecules Cr,O3
52.00
mol O2
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Transcribed Image Text:4:49 1 LTE Question 17 of 24 Submit Determine the number of molecules of Cr,O3 that form when 1.34 x 10³g of oxygen completely reacts according to the following equation: 4 Cr(s) + O2(g) → 2 Cr,03(s) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 2.52 x 1025 6.022 x 1023 g Cr 3.78 x 1025 4 g Cr,03 2 1.68 x 1025 g O2 1 4.24 x 103 mol Cr,O3 1.34 x 103 32.00 mol Cr 152.00 molecules Cr,O3 52.00 mol O2 Tap here or pull up for additional resources
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