Determine the Rate and Rate Constant CK). Equation 1: 2I'cae) + Sa Og* Cag) Iaca@)+aS0Caq) Equation 2: Rate= Egoaion 3: Rate = K[I]" [Sa0^ : ACS20,]. [7 4Cr.] [Bo7] 2At ACI] Bo] %3D 24t Fouation 4: I2 (a2) *2 SəOz*iaq)→cag) + SyO Cag) A[S.0,7 1[3305 Jorig AtSaO,-K [I[B_O/" Equaition 5: Rates - Equation6: Rate:- (rate law) Rate of lass Of reactant SaO"=Alsa05 5.00:10-M These are all of the equations given . II 1. -in order to e ion with perox- y carefully measured va,S,O, solution should be .ette. The KCl and (NH),SO, solu- -crs. Table 3: Initial Rates erefore: **Rate Constant, k **Rate Ra * [S,0,²1mt linit * [Fait init Rate Rxn # can be solved foI 0.0400M 0.0800M data from Rx 0.0400M erature, k sho trations. O.0400M O.0200M 0.0800M 0.0100M carily stain y 0.0800M 4 0.0300M 0.0600M with wate Average value for k Rate Rate Law:
Determine the Rate and Rate Constant CK). Equation 1: 2I'cae) + Sa Og* Cag) Iaca@)+aS0Caq) Equation 2: Rate= Egoaion 3: Rate = K[I]" [Sa0^ : ACS20,]. [7 4Cr.] [Bo7] 2At ACI] Bo] %3D 24t Fouation 4: I2 (a2) *2 SəOz*iaq)→cag) + SyO Cag) A[S.0,7 1[3305 Jorig AtSaO,-K [I[B_O/" Equaition 5: Rates - Equation6: Rate:- (rate law) Rate of lass Of reactant SaO"=Alsa05 5.00:10-M These are all of the equations given . II 1. -in order to e ion with perox- y carefully measured va,S,O, solution should be .ette. The KCl and (NH),SO, solu- -crs. Table 3: Initial Rates erefore: **Rate Constant, k **Rate Ra * [S,0,²1mt linit * [Fait init Rate Rxn # can be solved foI 0.0400M 0.0800M data from Rx 0.0400M erature, k sho trations. O.0400M O.0200M 0.0800M 0.0100M carily stain y 0.0800M 4 0.0300M 0.0600M with wate Average value for k Rate Rate Law:
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 36QRT
Related questions
Question
Reaction 1: 47.2 seconds
Reaction 2: 90.2 seconds
Reaction 3: 93.1 seconds
Reaction 4: 196.5 seconds
Reaction 5: 78.4 seconds
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