Direction: Read and understand the ff. set of monohybrid cross problems and answer each problem by showing the Punnett square, genotypes ans phenotypes. 1. In guinea pigs, short hair, S, is dominant to long hair, s. a. One guinea pig is Ss and one is ss. b. Both guinea pigs are heterozygous for short hair.
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- Monohybrid Cross Worksheet Directions: Answer each of the following questions using a Punnett Square and the rules of monohybrid crosses. The allele for dimples (D) is dominant to the allele for no dimples (d). A man heterozygous for dimples marries a woman who is also heterozygous for dimples. What is the man’s genotype and the woman’s genotype? What is the man’s phenotype and the woman’s phenotype? Do a cross to determine all potential dimple genotypes and phenotypes for the offspring of this man and woman. The allele for hitchhiker’s thumb (h) is recessive to straight thumb (H). If a man and his wife are both homozygous recessive, will any of their offspring potentially have hitchhikers thumb? What is the man’s genotype and the woman’s genotype? What is the man’s phenotype and the woman’s phenotype? What genotype(s) must the offspring have in order to have the phenotypic trait of hitchhiker’s thumb? Do a cross to determine all potential hitchhiker’s…I. Perform the indicated single-gene and two-gene crosses. Show all work. Show all Punnett squares. List the gene or genes involved, list and define all allele symbols, and indicate the genotypes of the individuals you are crossing above the Punnett square. Answer questions that ask for a ratio as a ratio and questions that ask for a percent as a percent. In humans, albinism is a recessively determined trait. One form of hereditary deafness is also a recessive trait. Show the cross of a man who is heterozygous for skin pigmentation and heterozygous for hereditary deafness with a woman who is albino and deaf. Show the expected phenotype ratio of the offspring.I. Perform the indicated single-gene and two-gene crosses. Show all work. Show all Punnett squares. List the gene or genes involved, list and define all allele symbols, and indicate the genotypes of the individuals you are crossing above the Punnett square. Answer questions that ask for a ratio as a ratio and questions that ask for a percent as a percent. One form of red-green color blindness is an X-linked recessive trait. A heterozygote woman has children with a normal man. What is the percentage chance that they will have a child with color blindness?
- I. Perform the indicated single-gene and two-gene crosses. Show all work. Show all Punnett squares. List the gene or genes involved, list and define all allele symbols, and indicate the genotypes of the individuals you are crossing above the Punnett square. Answer questions that ask for a ratio as a ratio and questions that ask for a percent as a percent. In humans, the allele for widow’s peak hairline is dominant to the allele for straight hairline. A woman with widow’s peak who is heterozygous marries a man with straight hairline and they decide to have children. Show the expected genotype ratio and phenotype ratio of the offspring. In snapdragon plants, the alleles for flower color show incomplete dominance. First show a cross of two parents, one with red flowers and the other with white flowers. Then show a cross of two of the F1 plants to get the F2 generation. Indicate the genotype ratio and phenotype ratio for both the F1 and F2 generations. A man with AB blood type…Cross a homozygous tall female carrier for hemophilia with a short normal male. Give genotypic and phenotypic ratios of the offspring. Use T = Tall, and t = short for one trait, and H =normal, and h = hemophilia for the second sex-linked trait. The Cross is: XHXhTT X XYtt . Question: What is the phenotypic ratio? a. 1:2:4:4 b. 4:4:4:4 c. 3:2:1:4 d. None is correctA. HUMAN PEDIGREE CASE ANALYSIS1. One couple has three children with the following sexes and ages: one son (40 y.o.) and two daughters (35 y.o. and 33 y.o.), all of them have normal pigmentation. Another couple has a son (35 y.o) and a daughter (20 y.o.) and all of them also have normal pigmentation. Both couples have normal pigmentation. The younger daughter from the first couple married the son of the second couple and they had three children. Their eldest daughter (5 y.o.) has normal pigmentation while their only son (3 y.o.) and one daughter (1 y.o.) have albinism. a. Draw the pedigree of this family. Follow protocols in making a pedigree. Provide the genotype of all individuals in the pedigree. Please provide also the gene notation. b. What is the mode of inheritance of this trait? c. Justify your answer in letter (b).d. For their normal daughter, what is the probability that she is a carrier? Show solution. e. If they will have a fourth child, what is the probability that the…
- 1. A woman who is heterozygous for hemophilia marries a man with hemophilia. What are the genotypes and phenotypes of the children? a) What is the genotypic ratio of the above cross (Write number next to genotype)? ___________________________________________________________________ b) What is the phenotypic ratio of the above cross? (Write number next to phenotype)? ___________________________________________________________________d. Write the genotypes of the parents used in the testcross using the correct notation Please I really need help with this thanksCross a homozygous tall female carrier for hemophilia with a short normal male. Give genotypic and phenotypic ratios of the offspring. Use T = Tall, and t = short for one trait, and H =normal, and h = hemophilia for the second sex-linked trait. The Cross is: XHXhTT X XYtt Question: What is the Ggenotypic ratio? a.) None is correct b.) 3:2:1:4 c.) 4:4:4:4 d.) 1:2:4:4
- Match the terms with the best description. ______ dihybrid cross a. bb ______ monohybrid cross b. AaBb AaBb ______ homozygous condition c. Aa ______ heterozygous condition d. Aa AaThe forked line and probability methods make use of what probability rule? test cross product rule monohybrid rule sum ruleUse the probability method to calculate the genotypes and genotypic proportions of a cross between AABBCc and Aabbcc parents.