RESEARCH METHODGAATTCCTTAAGGAGTTCCTCAAGGAATTCCTTAAGGAGTTCCTCAAGLong fragmentsShort fragmentsТуре 1homozygote homozygote HeterozygoteТуре 2Sа.The individuals colored blue are affected by hemophelia, a blood clotting disease.b. They genotyped (determined the RFLP polymorphism, type 1 or type 2) of daughter1’sfamily with the results shown below:husbanddaughter1Are the RFLP and the hemophilia gene linked? Explain your reasoning.

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Description: RESEARCH METHODGAATTCCTTAAGGAGTTCCTCAAGGAATTCCTTAAGGAGTTCCTCAAGLong fragmentsShort fragmentsТуре 1homozygote homozygote HeterozygoteТуре 2Sа.The individuals colored blue are affected by hemophelia, a blood clotting disease.b. They genotyped (determi

RFLP It is abbreviated as Restriction fragment length polymorphism. It is defined as a type of…

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RESEARCH METHOD GAATTC CTTAAG GACTTC CICAAC GAA CT TTC AAG GAGTTC CICAAG Long fragments Short fragments Туре 1 homozygote Туре 2 homozygote Heterozygote The individuals colored blue are affected by hemophelia, a blood clotting disease. а. b. They genotyped (determined the RFLP polymorphism, type 1 or type 2) of daughter1's family with the results shown below: husband daughter1 Are the RFLP and the hemophilia gene linked? Explain your reasoning.

RESEARCH METHOD GAATTC CTTAAG GACTTC CICAAC GAA CT TTC AAG GAGTTC CICAAG Long fragments Short fragments Туре 1 homozygote Туре 2 homozygote Heterozygote The individuals colored blue are affected by hemophelia, a blood clotting disease. а. b. They genotyped (determined the RFLP polymorphism, type 1 or type 2) of daughter1's family with the results shown below: husband daughter1 Are the RFLP and the hemophilia gene linked? Explain your reasoning.

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter4: Pedigree Analysis In Human Genetics

Section: Chapter Questions

Problem 19QP: Analysis of X-Linked Dominant and Recessive Traits Suppose a couple, both phenotypically normal,...

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Fruit flies with one allele for curly wings (Cy) andone allele for normal wings (Cy+) have curly wings.When two curly-winged flies were crossed, 203curly-winged and 98 normal-winged flies wereobtained. In fact, all crosses between curly-wingedflies produce nearly the same curly : normal ratioamong the progeny.a. What is the approximate phenotypic ratio in theseoffspring?b. Suggest an explanation for these data.c. If a curly-winged fly was mated to a normalwinged fly, how many flies of each type would youexpect among 180 total offspring?
HUMAN KARYOTYPE ANALYSISAnswer the following questions based on the given karyotype below:(see attched) a. What is the chromosome number of the individual? ___________________b. Give the sex of the individual. ______________c. Based from the karyotype, identify the name of the genetic condition of the individual. Listdown two (2) distinctive characteristics of the affected individual.
A man is brachydactylous (very short fingers; rare autosomal dominant), and his wife is not. Both can taste thechemical phenylthiocarbamide (autosomal dominant;common allele), but their mothers could not.a. Give the genotypes of the couple.If the genes assort independently and the couple hasfour children, what is the probability ofb. all of them being brachydactylous?c. none being brachydactylous?d. all of them being tasters?e. all of them being nontasters?f. all of them being brachydactylous tasters?g. none being brachydactylous tasters?h. at least one being a brachydactylous taster?
.Certain forms of human color blindness are inherited as X-linkedrecessive traits. Hemizygous males are color-blind, but heterozygous females are not. However, heterozygous females sometimeshave partial color blindness.A. Discuss why heterozygous females may have partial color blindness.B. Doctors identified an unusual case in which a heterozygousfemale was color-blind in her right eye but had normal colorvision in her left eye. Explain how this might have occurred.
Need help, please. What are the ratios for the progeny phenotype(s)?
Two normal-looking fruit flies were crossed, and, in the progeny, there were 202 females and 98 males.a. What is unusual about this result?b. Provide a genetic explanation for this anomaly.c. Provide a test of your hypothesis.
Analysis of X-Linked Dominant and Recessive Traits Suppose a couple, both phenotypically normal, have two children: one unaffected daughter and one son affected with a genetic disorder. The phenotype ratio is 1:1, making it difficult to determine whether the trait is autosomal or X-linked. With your knowledge of genetics, what are the genotypes of the parents and children in the autosomal case? In the X-linked case?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
Clubfoot is a common congenital birth defect. This defect is caused by a number of genes but appears to be phenotypically distributed in a noncontinuous fashion. Geneticists use the threshold model to explain the occurrence of this defect. Explain this model. Explain predisposition to the defect in an individual who has a genotypic liability above the threshold versus an individual who has a liability below the threshold.
The accompanying pedigree shows a very unusual inheritance pattern that actually did exist. All progeny areshown, but the fathers in each mating have been omittedto draw attention to the remarkable pattern.a. Concisely state exactly what is unusual about thispedigree.b. Can the pattern be explained by Mendelianinheritance?