Dole Food Company, Inc., is the world's largest producer and marketer of fresh fruit and vegetables. Dole grows and sources from independent growers and transports bananas grown primarily in Colombia, Costa Rica, Ecuador, Guatemala and Honduras for markets principally in North America, Europe, the Mediterranean and selected Asian markets. A Dole inspector took a random sample of crates of bananas prior to shipment. The weights of the crates sampled, in pounds, are as follows: 24.95, 25.15, 25.32, 23.88, 26.16, 25.09, 24.96, 25.48, 24.75, and 24.76. The population of banana weights are assumed to be normally distributed. Construct a 90% confidence interval for the mean population weight of all crates of Dole bananas. Use only the appropriate formula and/or statistical table in your textbook to answer this question. Negative amounts should be indicated by a minus sign. Report your answer to 2 decimal places, using conventional rounding rules. Answer:   ≤   (Click to select)   p   x-bar   μ   s   n   σ   π  ≤  pounds

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Asked Dec 6, 2019
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Dole Food Company, Inc., is the world's largest producer and marketer of fresh fruit and vegetables. Dole grows and sources from independent growers and transports bananas grown primarily in Colombia, Costa Rica, Ecuador, Guatemala and Honduras for markets principally in North America, Europe, the Mediterranean and selected Asian markets. A Dole inspector took a random sample of crates of bananas prior to shipment. The weights of the crates sampled, in pounds, are as follows: 24.95, 25.15, 25.32, 23.88, 26.16, 25.09, 24.96, 25.48, 24.75, and 24.76. The population of banana weights are assumed to be normally distributed. Construct a 90% confidence interval for the mean population weight of all crates of Dole bananas. Use only the appropriate formula and/or statistical table in your textbook to answer this question. Negative amounts should be indicated by a minus sign. Report your answer to 2 decimal places, using conventional rounding rules.

 

Answer:   ≤   (Click to select)   p   x-bar   μ   s   n   σ   π  ≤  pounds

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Expert Answer

Step 1

From the given information, 

Sample data:

24.95, 25.15, 25.32, 23.88, 26.16, 25.09, 24.96, 25.48, 24.75, and 24.76.

Significance level (α) = 0.10

Degree of freedom = n – 1

                                       = 10 -1

                                      = 9

T- Critical value = ±1.833 (using t table)

Step 2

Sample mean and sample standard de...

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Σ 24.95 + 25.15 + . +24.76 ....... 10 = 25.05 %3D Σ(x-3) n-1 24.95 – 25.05) +(25.15 – 25.05)´ +. +(24.76 – 25.05) 10-1 = 0.583 %3D

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