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Draw the fragmented molecular ion for the compound shown above for peaks 127,144 and 159. Thank you.
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- Estimate the Km and vmax from the data. [S] (M) Velocity (µM/min) 2.5 x 10-6 28 .00001 70 .00004 112 .0001 128 .002 139 .01 140 Km=.00001 vmax=140 Km=.002 vmax=112 Km=.01 vmax=140 Km=.00001 vmax=70If 5 µM enzyme was used to obtain the data in the summary plot below, V-max = ________________ µM sec-1 and Km = ____________ µM for this enzyme (Enter numeric values to the nearest integer; Do NOT write units.)NH4+ {aq) + NO2(aq) -> N2(g) +2H2O{l} Data Initial [NH4+] Initial [NO2-] rate 1 0.0100 0.200 5.4 x10-7 2 0.0200 0.200 10.8x10-7 3 0.0400 0.200 21.5x10-7 4 0.200 0.0202 10.8x10-7 5 0.200 0.0404 21.6x10-7 6 0.200 0.0808 43.3x10-7 Find x,y,k
- 1. Which of the following is NOT a true representation of the Lineweaver-Burk equation? Group of answer choices a. y-intercept = -1/Vmax b. x-intercept = -1/Km c. y = 1/V0 d. x = 1/[S] e. slope = Km/Vmax 2. If the y-intercept of a Lineweaver-Burk (double reciprocal) plot = 39.37 (sec/millimole) and the slope = 75.3 L/sec, Vmax equals: Group of answer choices a. 75.3 millimoles/sec. b. 0.0254 millimoles/sec. c. 0.523 millimoles/sec. d. 39.4 millimoles/sec. 3. Which of the following is true regarding allosteric enzyme behavior?Group of answer choices a. Allosteric enzymes are rarely important in the regulation of metabolic pathways. b. An allosteric effector binds reversibly on the surface of the enzyme. c. An hyperbolic representation of the relation initial velocity vs [S] is a specific characteristic of an allosteric enzyme behavior. d. Michaelis-Menten kinetics model the kinetic behavior of allosteric enzymes.Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any âdriftâ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…Hello, can someone please help me? I have already hand graphed 1 and 2 and found the v max, however I cannot find the Km value. I am confused because the plots on the linear weaver burk plot do not extend past the values that make up the line. So how am I supposed to estimate the value for the y-intercept in order to find the Km value
- calculate the flow rate in ml/hr . order 40meq/l at 10meq/hr in 1000ml in d5w supply 20meq/10mlplease help this is my 4th time posting this and i havent gotten a correct answer. Please actually draw the graph out. A newly discovered enzyme, MBCase, cleaves carbon-carbon bonds of vicinal alcohol; The kinetic parameters were measured for 1.0 nM Of MBGase and determined to be a Km = 10 nM and a kcat = 100 s-1 a.) Sketch the graph out as a double-reciprocal plot (Lineweaver-Burke Plot) and label: -the axes (with units) -the point on the curve that can be used to determine Km -the point on the curve that can be used to determine VmaxShow all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdk
- Ee.5. With explanation please....There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…