Draw the structure with the molecular formula CgH140 that most likely produced the below IR and H NMR. The 13C NMR data is 78.3 ppm, 43.9 ppm, 27.3 ppm, 13.3 ppm. 100 80- 60 - 40- 20 1460 3400 2940 1370 1160 4000 3500 3000 2500 2000 1500 1000 500 Wavenumbers (cm-1)

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Draw the structure with the molecular formula CgH140 that most likely produced the below IR and H NMR. The 13C NMR data is 78.3 ppm, 43.9
ppm, 27.3 ppm, 13.3 ppm.
100
80-
60 -
40-
20
1460
3400
2940
1370
1160
4000
3500
3000
2500
2000
1500
1000
500
Wavenumbers (cm-1)
Transcribed Image Text:Draw the structure with the molecular formula CgH140 that most likely produced the below IR and H NMR. The 13C NMR data is 78.3 ppm, 43.9 ppm, 27.3 ppm, 13.3 ppm. 100 80- 60 - 40- 20 1460 3400 2940 1370 1160 4000 3500 3000 2500 2000 1500 1000 500 Wavenumbers (cm-1)
8 20
1460
3400
2940
1370
1160
4000
3500
3000
2500
2000
1500
1000
500
Wavenumbers (cm-1)
singlet
6H
doublet
6H
broad
septet
1H
singlet
1H
8
6.
4
2
Chemical shift (ppm)
1st attempt
6 OF 25 QUESTIONS COMPLETED
の10
Transcribed Image Text:8 20 1460 3400 2940 1370 1160 4000 3500 3000 2500 2000 1500 1000 500 Wavenumbers (cm-1) singlet 6H doublet 6H broad septet 1H singlet 1H 8 6. 4 2 Chemical shift (ppm) 1st attempt 6 OF 25 QUESTIONS COMPLETED の10
Expert Solution
Step 1

Identification of organic compound can be done by spectroscopic techniques. 

The techniques are : IR, 1H-NMR and 13C-NMR.  

Chemical shift value of a proton/C depends on the electronic environment. Greater is the electron deficiency, higher will be the chemical shift value. 

Splitting of a proton is based on the (n+1) rule where n is the no of chemically non-equivalent protons. 

 

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