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e. 9.50 H: 14-5.4413 ZpH=8.50 [OH ]=V1445 xlo- COH-7=3.180Ix 10-6. " •(0.70) Ja 11. A buffer solution is made by adding 0.30 moles of ammonium perchlorate (NH4CIO4) and 0.4 ammonia to 1.0 L of water. If 0.050 mole of sodium hydroxide is added to 500.0 mL of this what is the resultant pH (Kb (NH3 ) = 1.8 x 10*) 4.21 b. 9.65 а. c. 11.34 rue Ca

e. 9.50 H: 14-5.4413 ZpH=8.50 [OH ]=V1445 xlo- COH-7=3.180Ix 10-6. " •(0.70) Ja 11. A buffer solution is made by adding 0.30 moles of ammonium perchlorate (NH4CIO4) and 0.4 ammonia to 1.0 L of water. If 0.050 mole of sodium hydroxide is added to 500.0 mL of this what is the resultant pH (Kb (NH3 ) = 1.8 x 10*) 4.21 b. 9.65 а. c. 11.34 rue Ca

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.141QP: Ka for formic acid is 1.7 104 at 25C. A buffer is made by mixing 529 mL of 0.465 M formic acid,...
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number 11 please?
10. What is the pH of a 0.70 M solution of NaNO2 (Ka of HNO2 = 6.92 × 10“) 070 7.50 - log734304 l0-6) =5.4975 a. b 10.50 8.50 6.92710- с. Kbal.445410 11. A buffer solution is made by adding (0.30 moles of ammonium perchlorate (NH4CIO4) and 0.40 moles of ammonia to 1.0 L of water. If 0.050 mole of sodium hydroxide is added to 500.0 mL of this buffer solution what is the resultant pH (Kb (NH3 ) = 1.8 x 10³) 4.21 d. 6.50 9.50 PAS 14-S.4975Y692 e. fOH-7=3.18041x lo-6 a. b. 9.65 11.34 с. Cen be a Puestion ņ or ApMa= 3.0 Ind c pha =9.0 n titnatons NH3 acldie Ind B pka =7.1 + HClNHyCL 2)aKoH +HNO3. neutrat 3. B sart p) st .0. KOH D Which equi [OH]=Vi.445 x10 (0.70) Ta pH=14-poH.
Transcribed Image Text:10. What is the pH of a 0.70 M solution of NaNO2 (Ka of HNO2 = 6.92 × 10“) 070 7.50 - log734304 l0-6) =5.4975 a. b 10.50 8.50 6.92710- с. Kbal.445410 11. A buffer solution is made by adding (0.30 moles of ammonium perchlorate (NH4CIO4) and 0.40 moles of ammonia to 1.0 L of water. If 0.050 mole of sodium hydroxide is added to 500.0 mL of this buffer solution what is the resultant pH (Kb (NH3 ) = 1.8 x 10³) 4.21 d. 6.50 9.50 PAS 14-S.4975Y692 e. fOH-7=3.18041x lo-6 a. b. 9.65 11.34 с. Cen be a Puestion ņ or ApMa= 3.0 Ind c pha =9.0 n titnatons NH3 acldie Ind B pka =7.1 + HClNHyCL 2)aKoH +HNO3. neutrat 3. B sart p) st .0. KOH D Which equi [OH]=Vi.445 x10 (0.70) Ta pH=14-poH.
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