Elemental analysis determined unknown Compound G to contain 40.0 % carbon, 6.7 % hydrogen. Compound G had an M+ = 60 m/z on its MS. Its IR displayed three absorbances: strong at 1710, strong below 3000, and broad from 2500 to 3500. The proton NMR showed an absorbance at 1.7 ppm (lowest whole number ratio of H =3), and an absorbance at 11.5 ppm (lowest whole number ratio of H = 1). Compound G was able to turn blue litmus paper red, and neutralize a base. What is Compound G? O CH3CO2H O Formaldehyde о но C CH2 HO O CHy(OH)CHO O CHIOH CH(OH)

Elemental analysis determined unknown Compound G to contain 40.0 % carbon, 6.7 % hydrogen. Compound G had an M+ = 60 m/z on its MS. Its IR displayed three absorbances: strong at 1710, strong below 3000, and broad from 2500 to 3500. The proton NMR showed an absorbance at 1.7 ppm (lowest whole number ratio of H =3), and an absorbance at 11.5 ppm (lowest whole number ratio of H = 1). Compound G was able to turn blue litmus paper red, and neutralize a base. What is Compound G? O CH3CO2H O Formaldehyde о но C CH2 HO O CHy(OH)CHO O CHIOH CH(OH)

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter13: Structure Determination: Nuclear Magnetic Resonance Spectroscopy

Section13.SE: Something Extra

Problem 64GP: Compound F, a hydrocarbon with M+=96 in its mass spectrum, undergoes reaction with HBr to yield...

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