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Employing the following data (at 25°C): 1/2H, (g)+1/20, (g)→ HO (g) AH=10.06 kcal mol" H, (g)+1/20, (g)→H,O (g) A,H=-57.80 kcal mol AH=104.178 kcal mol" AH=118.318 kcal mol- ' H, (g)→ 2H (g) O, (g) → 20 (g) assuming ideal behaviour, calculate the AH and AU of the following ctions: HO (g) → H (g)+ O (g) H,0 (g) → 2H (g) +O (g) H,0 (g) →H (g)+ HO (g)

Employing the following data (at 25°C): 1/2H, (g)+1/20, (g)→ HO (g) AH=10.06 kcal mol" H, (g)+1/20, (g)→H,O (g) A,H=-57.80 kcal mol AH=104.178 kcal mol" AH=118.318 kcal mol- ' H, (g)→ 2H (g) O, (g) → 20 (g) assuming ideal behaviour, calculate the AH and AU of the following ctions: HO (g) → H (g)+ O (g) H,0 (g) → 2H (g) +O (g) H,0 (g) →H (g)+ HO (g)

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter23: Organic Polymers, Natural And Synthetic
Section: Chapter Questions
Problem 46QAP: Glycolysis is the process by which glucose is metabolized to lactic acid according to the equation...
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Employing the following data (at 25ºC):

and assuming ideal behaviour, calculate the ΔH and ΔU of the following
reactions:

Employing the following data (at 25°C): 1/2H, (g)+1/20, (g)→ HO (g) AH=10.06 kcal mol"1 A,H=-57.80 kcal mol" H, (g)+1/20, (g)→H,O (g) H, (g)→ 2H (g) AH=104.178 kcal mol- 0, (g) →20 (g) AH=118.318 kcal mol- assuming ideal behaviour, calculate the AH and AU of the following ctions: HO (g) →H (g)+O (g) H,0 (g) → 2H (g) +O (g) H,0 (g) →H (g)+HO (g)
Transcribed Image Text:Employing the following data (at 25°C): 1/2H, (g)+1/20, (g)→ HO (g) AH=10.06 kcal mol"1 A,H=-57.80 kcal mol" H, (g)+1/20, (g)→H,O (g) H, (g)→ 2H (g) AH=104.178 kcal mol- 0, (g) →20 (g) AH=118.318 kcal mol- assuming ideal behaviour, calculate the AH and AU of the following ctions: HO (g) →H (g)+O (g) H,0 (g) → 2H (g) +O (g) H,0 (g) →H (g)+HO (g)
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