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Energy to sublime K(s) = 89.0 kJ/mol %3D Electron affinity of F(g) = -328.0 kJ/mol First ionization energy of K(g) = 425.0 kJ/mol Bond energy of F2(g) = 154.0 kJ/mol AHon for K(s) + 1/2 F2(g) → → KF(s) = -562.6kJ/mol %3! 1st attempt Determine the lattice energy of KF(s), using the data provided. kJ/mol

Energy to sublime K(s) = 89.0 kJ/mol %3D Electron affinity of F(g) = -328.0 kJ/mol First ionization energy of K(g) = 425.0 kJ/mol Bond energy of F2(g) = 154.0 kJ/mol AHon for K(s) + 1/2 F2(g) → → KF(s) = -562.6kJ/mol %3! 1st attempt Determine the lattice energy of KF(s), using the data provided. kJ/mol

Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
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Energy to sublime K(s) = 89.0 kJ/mol Electron affinity of F(g) = -328.0 kJ/mol First ionization energy of K(g) = 425.0 kJ/mol %3D Bond energy of F2(g) = 154.0 kJ/mol AHxn for K(s) + 1/2 F2(g) → KF(s) = -562.6 kJ/mol %3D 1st attempt O See Hint Determine the lattice energy of KF(s), using the data provided. kJ/mol
Transcribed Image Text:Energy to sublime K(s) = 89.0 kJ/mol Electron affinity of F(g) = -328.0 kJ/mol First ionization energy of K(g) = 425.0 kJ/mol %3D Bond energy of F2(g) = 154.0 kJ/mol AHxn for K(s) + 1/2 F2(g) → KF(s) = -562.6 kJ/mol %3D 1st attempt O See Hint Determine the lattice energy of KF(s), using the data provided. kJ/mol
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