Enter your answer in the provided box. Hydrogen sulfide decomposes according to the following reaction, for which = 9.30 × 10 -8 at 700°C: 2 H,S(g) = 2 H,g) + S2(g) If 0.35 mol of H,S is placed in a 3.0-L container, what is the equilibrium concentration of H2(g) at 700°C?

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Chapter18: Thermodynamics And Equilibrium
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Hydrogen sulfide decomposes according to the following reaction, for which
K.
= 9.30 × 10-8
at 700°C:
2 H2S(g) = 2 H2(g)+ S2(g)
If 0.35 mol of H2S is placed in a 3.0–L container, what is the equilibrium concentration of H2(g) at
700°C?
Transcribed Image Text:Enter your answer in the provided box. Hydrogen sulfide decomposes according to the following reaction, for which K. = 9.30 × 10-8 at 700°C: 2 H2S(g) = 2 H2(g)+ S2(g) If 0.35 mol of H2S is placed in a 3.0–L container, what is the equilibrium concentration of H2(g) at 700°C?
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