Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter19: Principles Of Chemical Reactivity: Electron Transfer Reactions
Section: Chapter Questions
Problem 84GQ: Calculate equilibrium constants for the following reactions at 208 K. Indicate whether the...
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Question
18
![Examine the following reaction.
3 CO 2 (g) +2 Fe( s) 5 Fe 203(s) + 3 CO(g)
What is the equilibrium expression for the reaction?
O K = [CO2]/[CO]3
O K = [Fe] [CO2] / ([Fe,O3] [CO])
O K = [Fe] [CO2]/ ([Fe2O3][CO])
O K = [Fe]/[Fe2O3]
%3D
%3D
O Kc = [Fe2O3] /[Fe]
O K = [Fe2O3] [Coj³ / ([Fe]? [CO2]®)
O Kc = [CO2]/[CO]
O K = [CO]/[CO2]
O Kc = [Fe2O3] [CO] / ([Fe] [CO2])
O K = [CO] /[CO2]3
%3D
%3D
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Transcribed Image Text:Examine the following reaction.
3 CO 2 (g) +2 Fe( s) 5 Fe 203(s) + 3 CO(g)
What is the equilibrium expression for the reaction?
O K = [CO2]/[CO]3
O K = [Fe] [CO2] / ([Fe,O3] [CO])
O K = [Fe] [CO2]/ ([Fe2O3][CO])
O K = [Fe]/[Fe2O3]
%3D
%3D
O Kc = [Fe2O3] /[Fe]
O K = [Fe2O3] [Coj³ / ([Fe]? [CO2]®)
O Kc = [CO2]/[CO]
O K = [CO]/[CO2]
O Kc = [Fe2O3] [CO] / ([Fe] [CO2])
O K = [CO] /[CO2]3
%3D
%3D
%3D
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