Exp NoExperinyElectraChean stoyVaydeo SbleVOl tage29NameKatherne EvaLab PartnerCourse &Section No.Desk NoCell RadknCoi ZnO270 V+ 2 ReducedFe+32-FeCell @eactionReitedO 362V3 2n 2COstae CoZntco Zna ColAxn4zn2n+ 12e41PedtedCellaxnAI3B2n2AO.479 VCOLU FELAWitness/TADateSignatureNote: Insert Divider Under Cop Sheet Before WTHE HAYDEN-MCNEIL STUDENT LAB NOTEBOOK

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Asked Nov 19, 2019
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POST LABORATORY QUESTIONS After Laboratory Homework Part 1 You have assumed your reference metal had a zero voltage contribution for your cell; have the relative voltage of each of the other four metals.  You are to calculate the voltage of the oxidation of your reference metal by adjusting each metal to the DEFINED scale relative to SHE.

 

Anode + Cathode = Voltage Reading so,                   Anode = Voltage Reading - Cathode

 

1.(a)  Find the Reduction Potentials for your metal ions to the metal:  Fe3+ to Zn2+ = 0.352 V, Cu2+ to Zn2+ = 0.270 V, Co2+ to Zn2+ = 0.254 V,    Al3+ to Zn2+ = 0.479 V.

 

1.(b)  Calculate your Anode from your Measured Voltage Reading  and the Reduction Potential, voltage, of each metal. 

 

1.(c)  Calculate the average value of your Anode.

 

1.(d)  Convert your voltage of the oxidation of the Anode to the reduction potential of your reference metal ion.

 

1.(e)  Calculate the percent difference of your reference metal ion reduction potential to the reduction potential found in the standard reduction from the Table of Reduction Potentials.

Exp No
Experiny
ElectraChean stoy
Vaydeo Sble
VOl tage
29
Name
Katherne Eva
Lab Partner
Course &
Section No.
Desk No
Cell Radkn
Coi Zn
O270 V
+ 2 Reduced
Fe+32-Fe
Cell @eaction
Reited
O 362V
3 2n 2
COstae Co
Zntco Zna Co
lAxn
4zn2n+ 12e
41
Pedted
Cellaxn
AI3B2n2A
O.479 V
COLU FELA
Witness/TA
Date
Signature
Note: Insert Divider Under Cop Sheet Before W
THE HAYDEN-MCNEIL STUDENT LAB NOTEBOOK
help_outline

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Exp No Experiny ElectraChean stoy Vaydeo Sble VOl tage 29 Name Katherne Eva Lab Partner Course & Section No. Desk No Cell Radkn Coi Zn O270 V + 2 Reduced Fe+32-Fe Cell @eaction Reited O 362V 3 2n 2 COstae Co Zntco Zna Co lAxn 4zn2n+ 12e 41 Pedted Cellaxn AI3B2n2A O.479 V COLU FELA Witness/TA Date Signature Note: Insert Divider Under Cop Sheet Before W THE HAYDEN-MCNEIL STUDENT LAB NOTEBOOK

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Expert Answer

Step 1

The given EMF values are wrong so here we use the standard electrode potential values and  the EMF of the cell is calculated by using below formula,

E E
-E
cell
'anode
'cathode
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E E -E cell 'anode 'cathode

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Step 2

From the standard reduction potentials,

Fe3
Fe 0.036
Cu2
Co2
A1 A-1.66 V
Cu 0.34
Co -0.28 V
Zn2
Zn -0.76 V
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Fe3 Fe 0.036 Cu2 Co2 A1 A-1.66 V Cu 0.34 Co -0.28 V Zn2 Zn -0.76 V

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Step 3

Substitute the above vales to get the standa...

Zn2
Fe3
--0.036-(-0.76)= 0.724 V
Е
cell
Cu2
Zn20.34-(0.76)
= 0.34- (-0.76)-110V
E
cell
Co2
Zn -0.28 V
E a0.28-(-0.76)=-0.48V
cell
Zn2-1.66 V
Al2
--0.76- (-1.66)= 0.9 V
E
cell
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Zn2 Fe3 --0.036-(-0.76)= 0.724 V Е cell Cu2 Zn20.34-(0.76) = 0.34- (-0.76)-110V E cell Co2 Zn -0.28 V E a0.28-(-0.76)=-0.48V cell Zn2-1.66 V Al2 --0.76- (-1.66)= 0.9 V E cell

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