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Experiment: E2 Elimination of 2-bromoheptane please hand written.
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- 1.Explain why pyridine ( Kb=2.3x10-9) is a much stronger base than pyrrole (Kb=2.5x10-14), 2.Explain and illustrate, why it is difficult to perfom Friedel-Craft reactions on unactivated pyridine.NO2 being a deactivating group, increase the acidic nature of alcohol, by increasing the stability of the corresponding conjugate base. True FalseFor the following groups of molecules (labeled A-C), rank the acidity of the molecules in order from least acidic (3) to most acidic (1). Explain your reasoning.
- Can you choose the right answer in each bracket? Inside the box (final step), [ester / ketone / amine / amide] functionality acts as a [ electrophile / nucleophile / acid / base] to attack [ester / ketone / amine / amide] functionality, which serves as a [ electrophile / nucleophile / acid / base]. These will react [intramolecularly / intermoleculary] to afford the [imine/ enamine/ amine / amide] functionality in the target compound.In benzoic acid, when it has a deactivating group in position "para" (relative to carboxylate position) , it attracts electrons towards it, weakening the acid and an activator pushes the electrons making the acid stronger.What happens to this benzoic acid if it has a substituent at the "meta" or "ortho" position as an activator or a deactivator? I need an explanation of what happens in each case pleasePlease answer this NEATLY, COMPLETELY, and CORRECTLY for an UPVOTE. Predict the major product for the addition of an acid (HBr) to the compound below.
- For the following pairs of alcohols, identify the one that is more acidic and explain your choice using ARIO. I said that the molecule on the left side was more acidic due to the e- withdrawing effect, however, my professor stated that resonance takes priority thus the molecule on the right side is the one that is more acidic. Can you explain to me why using ARIO? Thanks in advance!Molecule 3 was prepared via molecules 1 and 2. Provide a complete curved arrow mechanism for the most straightforward conversion to 3. You can use HA as your acid and A- as your base.The pKa of our product is ~ 2-3 units lower than the pKa of phenol. Draw all possible resonance structures of the conjugate base of the product, and use these to explain why our product is so much more acidic than phenol.
- Carboxylic Acid Draw complete electron flow mechanisms for the following reactions.The product in this reaction is basic enough to be protonated by a dilute HCl solution. Draw the protonated species, clearly showing where protonation occurs. Draw all possible resonance structures of the conjugate acid of the product, and use these to explain why the product is so much more basic than a typical ester, like ethyl acetate.Using the retrosynthetic analysis propose a logical route for the following transformation. Draw all substrates, reagents and products