Explain your experimental approach if you must correct the genetic defect phenylketonuria (PKU), which is caused by mutations in the phenylalanine hydroxylase (PAH) gene using the CRISPR/Cas9 system and homology directed DNA repair.
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Explain your experimental approach if you must correct the genetic defect phenylketonuria (PKU), which is caused by mutations in the phenylalanine hydroxylase (PAH) gene using the CRISPR/Cas9 system and homology directed DNA repair.
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- please help me with thi question. What advantages do CRISPR‑Cas systems have over restriction enzymes and engineered nucleases for editing DNA? The options are attached. Multiple answers can be chosenplease answer these questions for this image What is the source of the DNA? What is the target? What vector is being used to move the DNA? What is the benefit of transforming the target cell in these ways?several options can be correct Consider the following segment of DNA, which is part of a linear chromosome: LEFT 5’.…TGACTGACAGTC….3’ 3’.…ACTGACTGTCAG….5’ RIGHT During RNA transcription, this double-strand molecule is separated into two single strands from the right to the left and the RNA polymerase is also moving from the right to the left of the segment. Please select all the peptide sequence(s) that could be produced from the mRNA transcribed from this segment of DNA. (Hint: you need to use the genetic codon table to translate the determined mRNA sequence into peptide. Please be reminded that there are more than one reading frames.) Question 6 options: ...-Asp-Cys-Gln-Ser-... ...-Leu-Thr-Val-... ...-Thr-Val-Ser-... ...-Leu-Ser-Val-... ...-Met-Asp-Cys-Gln-...
- options for each are: primase, topoisomerase, dnaB, dnaA, Pol IIIAmplified target regions of four different samples were separated using gel electrophoresis. DNA fragments labeled with the isotope P32 were separated by gel electrophoresis. The ultimate reason why unique target regions within each sample separate from each other in the gel is due to Amplified target regions of four different samples were separated using gel electrophoresis. DNA fragments labeled a) the amount of P32 bonded to each fragment. b) the number of restriction sites in each fragment. c) the distance between the primer recognition sites. d) the number of positive charges in each fragment.please help me with this question. As this is a non-directional cloning, recombinant plasmids can contain an insert ligated into the vector in two different orientations. Provide two diagrams to illustrate the two potential recombinant plasmids, with the inserts ligated in opposite orientations. Include all RE sites and distances between sites on the diagram.
- Will you please help me in understanding these? How many fragments will be formed after digestion in sample C, if the plasmid is circular and why? What are the critical steps in transformation? How was RAD52 expression observed? Provide current applications of DNA TechnologyEhat primer sets could be amplify the following DNA sequence? AATACGTCGCATGGggatccttttttatgcatgDNA polymerase error rates can be 10-8 to 10° per nucleotide, and mutations in the repair functions of DNA polymerases that increase error rates can cause reduced survival phenotypes. Yet RNA polymerase error rates can be as high as 3 x105. Why is it so much more important for DNA polymerase to be accurate than RNA polymerase? Be brief.
- How can the genetic defect phenylketonuria (PKU), which is caused by mutations in the phenylalanine hydroxylase (PAH) gene be corrected by using the CRISPR/Cas9 system and homology directed DNA repair.Detail the differences between base excision repair and nucleotide excision repair. Please help explain in 5 sentences or less, thank you!Please answer asap and type your answer and do not copy from anywhere please NOTE*** double stranded complementary DNA I have determined is GTCATACCTAGGGTA with a palindromic site of CCTAGG and the enzyme BamHI that will cut the recognition site. In the double-stranded DNA you have determined, there is also another recognition site for common restriction enzymes. Which enzyme would cut your DNA at this other recognition site? (Hint: Remember that one recognition site can overlap with or be completely contained by the sequence containing another recognition site.) HindIII Sau3AI AluI BamHI