Fe(s) + 2HCI(aq)→FeCl2(s) + H2(g) for which AH° = -7.400 kJ and AS° = 107.9 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 2.465 moles of Fe(s) react under standard conditions at 298.15 K. ASuniverse = J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'.
Fe(s) + 2HCI(aq)→FeCl2(s) + H2(g) for which AH° = -7.400 kJ and AS° = 107.9 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 2.465 moles of Fe(s) react under standard conditions at 298.15 K. ASuniverse = J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'.
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter13: Spontaneous Processes And Thermodynamic Equilibrium
Section: Chapter Questions
Problem 22P: Use data from Appendix D to calculate the standardentropy change at 25°C for the reaction...
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Transcribed Image Text:Fe(s) + 2HCI(aq).
→F€C12(s) + H2(g)
for which AH° = -7.400 kJ and AS° = 107.9 J/K at 298.15 K.
(1) Calculate the entropy change of the UNIVERSE when 2.465 moles of Fe(s) react under standard conditions at 298.15 K.
AS,
Suniverse
J/K
(2) Is this reaction reactant or product favored under standard conditions?
(3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'.
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