Question
Asked Nov 8, 2019
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29.57     The long, straight wire shown in Fig. P29.57a carries constant current I.  A metal bar with length L is moving at constant velocity v, as shown in the figure.  Point a is a distance d from the wire.

(a) Calculate the emf induced in the bar.

(b) Which point, a or b, is at higher potential?

(c) If the bar is replaced by a rectangular wire loop of resistance R (Fig. P29.57b), what is the magnitude of the current induced in the loop?

Hint: (b) and (c) are conceptual questions.

Figure P29.57
(a)
(b)
L
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Figure P29.57 (a) (b) L

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Expert Answer

Step 1

https://www.bartleby.com/questions-and-answers/figure-p29.57-a-b-l/8803fba2-0928-46cc-abca-f96d5e905401

a)

As shown from the diagram, divide the total length of the rod into small number of elements dx which is at a distance x from current carrying wire.

Magnitude of magnetic field due to current carrying ire at a distance x from the element is

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L В- 2лr

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Step 2

The induced emf in a rod moves normal to magnetic field is

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E=6(VXB|d dr 2Tr ovIar 2л integrating the above equation be tween the limits d to d+ 2T r d d+L -[1nx \d 2л In(d +L)-Ind 2л (d In -L)

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Step 3

b)

The magnitude of force acting on moving...

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F-axB

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