For a particular process that is carried out at constant pressure, q = 145 kJ and w = -35kJ. Therefore, AE = 180 kJ and AH = 145 kJ AE = 110 kJ and AH = 145 kJ AE = 145 kJ and AH = 110 kJ AE = 145 kJ and AH= 180 kJ

For a particular process that is carried out at constant pressure, q = 145 kJ and w = -35kJ. Therefore, AE = 180 kJ and AH = 145 kJ AE = 110 kJ and AH = 145 kJ AE = 145 kJ and AH = 110 kJ AE = 145 kJ and AH= 180 kJ

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter2: The First Law Of Thermodynamics

Section: Chapter Questions

Problem 2.10E: Calculate the specific heat of a material if 288J of energy were required to heat 50.5g of the...

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For a particular process that
is carried out at constant
pressure, q = 145 kJ and w =
-35 kJ. Therefore,
AE = 180 kJ and AH = 145
kJ
AE = 110 kJ and AH = 145
kJ
AE = 145 kJ and AH= 110
kJ
AE = 145 kJ and AH = 180
kJ

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