3 For an 18-8 Mo stainless steel (Animated Figure 8.36), predict the time to rupture for a component that is subjected to a stress of 80MPa(11,600 psi) at 700°C (973 K).hourseTextbook and MediaSave for LaterAttempts: 0 of 3 usedSubmit Anwer Stress (MPa)Stress (psi)T(20 + log t,)(R-h)Larson-Miller parameter =42.42 10 (R-h)253035x103 x103404550x103x103 x103 x103Larson-Miller parameter =100,000 23.24 - 10 (K-h)Stress = 80 MPAStress = 11.6 10 psi%3D10010,00010100024x1032012x10316x10328x103x103T(20 + log t,)(K-h)

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For an 18-8 Mo stainless steel (Animated Figure 8.36), predict the time to rupture for a component that is subjected to a stress of 80 MPa(11.600 psi) at 700°C (973 K). hours eTextbook and Media Attempts: 0 of 3 used Submit Answer Save for Later

For an 18-8 Mo stainless steel (Animated Figure 8.36), predict the time to rupture for a component that is subjected to a stress of 80 MPa(11.600 psi) at 700°C (973 K). hours eTextbook and Media Attempts: 0 of 3 used Submit Answer Save for Later

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Fluid Kinematics

The branch of science that deals with objects which are either in motion or stationary are studied under the branch of classical mechanics. Fluid mechanics is a subcategory of classical mechanics that deals with the behavior of fluids at rest (fluid statics) or in motion (posing some velocity). In fluid kinematics, studies focus on the associated motion of fluid particles or groups of particles, and its associated parameters like displacements, velocity, and acceleration without concerning about the forces that caused the motion. All the laws of classical mechanics are applied in the study of fluid kinematics.

Question

For an 18-8 Mo stainless steel (Animated Figure 8.36), predict the time to rupture for a component that is subjected to a stress of 80
MPa(11,600 psi) at 700°C (973 K).
hours
eTextbook and Media
Save for Later
Attempts: 0 of 3 used
Submit Anwer

Stress (MPa)
Stress (psi)
T(20 + log t,)(R-h)
Larson-Miller parameter =
42.42 10 (R-h)
25
30
35
x103 x103
40
45
50
x103
x103 x103 x103
Larson-Miller parameter =
100,000 23.24 - 10 (K-h)
Stress = 80 MPA
Stress = 11.6 10 psi
%3D
100
10,000
10
1000
24
x103
20
12
x103
16
x103
28
x103
x103
T(20 + log t,)(K-h)

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