For the reaction: 2 Al (s) + 6 HC1 (g) 2 AlCla (s) + 3 H2 (g) calculate: 8.the moles of aluminum required theoretically to produce 854 g of aluminum chloride. For the reaction: 2 Al (s) + 6 HC1 (g) → 2 AIC1: (s) + 3 H2 (g) 9.what mass of hydrogen can be produced theoretically from 164 g of hydrogen chloride? For the reaction: 2 Al (s) + 6 HC1 (g) 2 AlCla (s) + 3 H2 (g) 10. what is the percent yield of this reaction if 48.8 g of hydrogen are actually produced from 539 g of aluminum?

World of Chemistry, 3rd edition
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Chapter9: Chemical Quantities
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8-10 i need help on with all being the same equation 

For the reaction: 2 Al (s) + 6 HC1 (g)
2 AlCla (s) + 3 H2 (g)
calculate:
8.the moles of aluminum required theoretically to produce 854 g of aluminum chloride.
For the reaction: 2 Al (s) + 6 HC1 (g)
→ 2 AIC1: (s) + 3 H2 (g)
9.what mass of hydrogen can be produced theoretically from 164 g of hydrogen chloride?
For the reaction: 2 Al (s) + 6 HC1 (g)
2 AlCla (s) + 3 H2 (g)
10.
what is the percent yield of this reaction if 48.8 g of hydrogen are actually produced
from 539 g of aluminum?
Transcribed Image Text:For the reaction: 2 Al (s) + 6 HC1 (g) 2 AlCla (s) + 3 H2 (g) calculate: 8.the moles of aluminum required theoretically to produce 854 g of aluminum chloride. For the reaction: 2 Al (s) + 6 HC1 (g) → 2 AIC1: (s) + 3 H2 (g) 9.what mass of hydrogen can be produced theoretically from 164 g of hydrogen chloride? For the reaction: 2 Al (s) + 6 HC1 (g) 2 AlCla (s) + 3 H2 (g) 10. what is the percent yield of this reaction if 48.8 g of hydrogen are actually produced from 539 g of aluminum?
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