For the reaction Fe2O3(s) + 3H2(g)2Fe(s) + 3H2O(g) H° = 98.8 kJ and S° = 143 J/K At standard conditions, this reaction would be product favored at relatively low temperatures. at no temperature. at relatively high temperatures. at all temperatures
For the reaction Fe2O3(s) + 3H2(g)2Fe(s) + 3H2O(g) H° = 98.8 kJ and S° = 143 J/K At standard conditions, this reaction would be product favored at relatively low temperatures. at no temperature. at relatively high temperatures. at all temperatures
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter13: Spontaneous Processes And Thermodynamic Equilibrium
Section: Chapter Questions
Problem 39P
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Hint: No calculations are required.
For the reaction
Fe2O3(s) + 3H2(g)2Fe(s) + 3H2O(g)
H° = 98.8 kJ and S° = 143 J/K
At standard conditions, this reaction would be product favored
For the reaction
Fe2O3(s) + 3H2(g)2Fe(s) + 3H2O(g)
H° = 98.8 kJ and S° = 143 J/K
At standard conditions, this reaction would be product favored
at relatively low temperatures.
at no temperature.
at relatively high temperatures.
at all temperatures.
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