For this double stranded DNA: 3’-AGGTCCAGTCTTCGGCGGATGATCGGGCCAACCCCCGTAACTGGTCACCGGAATGCC-5’ 5’-TCCAGGTCAGAAGCCGCCTACTAGCCCGGTTGGGGGCATTGACCAGTGGCCTTACGG -3’ , while using the bottom strand is the template for transcription. If the START CODON is AUG and the STOP CODON IS UGA, how many amino acids are in the encoded protein and what is the primary structure?

For this double stranded DNA: 3’-AGGTCCAGTCTTCGGCGGATGATCGGGCCAACCCCCGTAACTGGTCACCGGAATGCC-5’ 5’-TCCAGGTCAGAAGCCGCCTACTAGCCCGGTTGGGGGCATTGACCAGTGGCCTTACGG -3’ , while using the bottom strand is the template for transcription. If the START CODON is AUG and the STOP CODON IS UGA, how many amino acids are in the encoded protein and what is the primary structure?

Name: For this double stranded DNA:3’-AGGTCCAGTCTTCGGCGGATGATCGGGCCAACCCCCGT
Uploaded: 2024-03-20T06:42:41.000Z
Channel: Bartleby
Description: For this double stranded DNA:3’-AGGTCCAGTCTTCGGCGGATGATCGGGCCAACCCCCGTAACTGGTCACCGGAATGCC-5’5’-TCCAGGTCAGAAGCCGCCTACTAGCCCGGTTGGGGGCATTGACCAGTGGCCTTACGG -3’, while using the bottom strand is the template for transcription. If the START CODON is AUG a

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter9: Gene Expression And Gene Regulation

Section: Chapter Questions

Problem 16QP: Given the following tRNA anticodon sequence, derive the mRNA and the DNA template strand. Also,...

See similar textbooks

Similar questions

Given the following tRNA anticodon sequence, derive the mRNA and the DNA template strand. Also, write out the amino acid sequence of the protein encoded by this message. tRNA: UAC UCU CGA GGC mRNA: protein: How many hydrogen bonds would be present in the DNA segment?
For this double stranded DNA: 3’-AGGTCCAGTCTTCGGCGGATGATCGGGCCAACCCCCGTAACTGGTCACCGGAATGCC-5’ 5’-TCCAGGTCAGAAGCCGCCTACTAGCCCGGTTGGGGGCATTGACCAGTGGCCTTACGG -3’ , while using the bottom strand is the template for transcription. If the START CODON is AUG and the STOP CODON IS UGA, what would it look like drawn out?
Consider the following DNA template: 5’-AAGAGGTTCCAATGCAGGCACTCACCAACTCTTAAATAAA-3’ 3’-TTCTCCAAGGTTACGTCCGTGAGTGGTTGAGAATTTATTT-5’ If the bottom DNA strand is used as template to transcribe mRNA, predict the amino acid sequence that would result from the process of translation. Met-Ala-Leu-Thr-Gln-Glu-Gly Met-Gly-Ser-Leu-Asn-Ser-Gln Met-Thr-Asn-Ser-Leu-Ala-Gln Met-Gln-Ala-Leu-Thr-Asn-Ser Met-Glu-Ala-His-Trp-Ser-Tyr
Assume a bacterial gene underwent a mutation, where a thymine base from an early portion of the coding sequence of the DNA is replaced with a cytosine (as illustrated below). Original sequence (coding strand): AGTTCCTACAAAATGGAGCTGTCTTGGCATGTAGTCTTT ...[Sequence continues with another 80 bases] New sequence: AGTTCCCACAAAATGGAGCTGTCTTGGCATGTAGTCTTT...[Sequence continues with another 80 bases] UAC encodes tyrosine, CAC encodes histine, per the coding table. (This question can be answered without use of the code table, but it is provided here as a resource.) What would the expected result of such a mutation be on the final protein product of the mutated gene (compared to the original, non-mutant product)? The protein will be very different from the original version, and likely non-functional. The protein will be cut short, ending after the first amino acid. There will be no protein produced at all. No change – the protein will be the same.…
Which of the following DNA strands, the top or bottom, would serve as a template for RNA transcription if the DNA molecule were to unwind in the indicated direction? 5′ ACGGACTGTACCGCTGAAGTCATGGACGCTCGA 3′ 3′ TGCCTGACATGGCGACTTCAGTACCTGCGAGCT 5′ ⎯⎯⎯⎯→ Direction of DNA unwinding What would be the resulting RNA sequence (written 5′→3′ )?
Given the following stretch of mRNA, what would be the sequence of the corresponding non-template DNA? 5' - UUG-CAA-UCG-CAG-UGC-CGC-AUA-GAU - 3' Group of answer choices 3' - AAC-GTT-AGC-GTC-ACG-GCG-TAT-CTA - 5' 5' - TTG-CAA-TCG-CAG-TGC-CGC-ATA-GAT - 3' 5' - AAC-GTT-AGC-GTC-ACG-GCG-TAT-CTA - 3' 3' - AAC-GUU-AGC-GUC-ACG-GCG-UAU-CUA - 5' 3' - TTG-CAA-TCG-CAG-TGC-CGC-ATA-GAT - 5'
The following sequence is a double stranded DNA. 5'ATTTGACAATGCGTTAGGCATGACTATGTATAATGCATGCCACATACT... 3' 3'TAAACTGTTACGCAATCCGTACTGATACATATTACGTACGGTGTATGA…5' -35 -10 +1 Where does RNA polymerase initially binds?
From the following DNA strand: AAGCTAGGATTGCC How many codons would be present?
The following are DNA fragments containing a small gene. The top strand is the coding strand. Transcribe all 5 groups and translate. Group A 5’-GGCAATGGGTTTGTGCAATTCTAAAAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACGTTAAGATTTTCAAAAATTAAG-5’ Group B 5’-GGCAATGGGTTTGTGAAATTCTAAAAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACTTTAAGATTTTCAAAAATTAAG-5’ Group C 5’-GGCAATGGGTTTGTGCAATTCTAAGAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACGTTAAGATTCTCAAAAATTAAG-5’ Group D 5’-GGCAATGGGTTTGTGCAATTCTAACAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACGTTAAGATTGTCAAAAATTAAG-5’ Group E 5’-GGCAATGGGTTTTGCAATTCTAAAAGTTTTTAATTC-3’ 3’-CCGTTACCCAAAACGTTAAGATTTTCAAAAATTAAG
The template strand of a double helical segment of DNA consists of the following sequence: 5’-GTAGCCTTAAGCGATCACCGTCCGTATTACTAGTGGCCAGACTCTTTTCACTCTCATGTATAGTTG-3’ Following translation process, what is the amino acid sequence that will be coded for? (show your answer using ONE-letter amino acid code starting from N-terminus to C-terminus)
The template strand of a double helical segment of DNA consists of the following sequence: 5’-GTAGCCTTAAGCGATCACCGTCCGTATTACTAGTGGCCAGACTCTTTTCACTCTCATGTATAGTTG-3’ Following translation process, what is the amino acid sequence that will be coded for? (show your answer using THREE-letter amino acid code starting from N-terminus to C-terminus)
If the mRNA sequence is 5'-UUU-CCC-AAA-3'.The DNA coding strand should be 5'-TTT-CCC-AAA-3' ?The DNA template strand should be 3'-AAA-GGG-TTT-5' ?So in the 5 to 3 direction, the DNA template strand should be 5'TTT-GGG-AAA-3' ?