
Give an

In case of regular languages, it is comparatively easy , but for Context Free languages. Pumping Lemma provides us with ability to perform negative test, i.e. if a language doesn’t satisfy pumping lemma, then we can definitely say that it is not context free, but if it satisfies, then the language may or may not be context free.
Pumping Lemma is more of a mathematical proof, takes more time and to apply it on context free languages is a tedious task and finding out counter example for complex language expressions is not much handful.
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- on A language L is called slithy if it contains at least two strings and has the following property: For every two strings x, y in L such that |x|< lyl, the string obtained by taking the first letter of y and inserting it at the start of x is also in L. For example, if L contains aaa and baaba, then it must also contain the string baaa. Prove by contradiction that every slithy language contains two strings of the same length.arrow_forwardADJUST Let L (a, ba) be a language over E= (a,b). TRUE or FALSE (with explanation): abab € L. Cancel AUTO ++ Revertarrow_forwardon A language L is called slithy if it contains at least two strings and has the following property: For every two strings x, y in L such that |x|< lyl, the string obtained by taking the first letter of y and inserting it at the start of x is also in L. For example, if L contains aaa and baaba, then it must also contain the string baaa. Prove by contradiction that every slithy language contains two strings of the same length.arrow_forward
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