Given: 4AICI3(s) + 302(g) → 2Al,03(s) + 6C12(g); AH =- 529.0 kJ determine AH for the following thermochemical equation. Cl2(3) + Al,03(s) → AIC13(s) + ¿O2(g) +88.2 kJ O +264.5 kJ O +176.3 kJ O -176.3 kJ O +529.0 kJ

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