Given a sorted array of distinct non-negative integers, find the smallest missing element in it.

Suppose an array sorted in ascending order is rotated at some pivot unknownto you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).Find the minimum element. The complexity must be O(logN)You may assume no duplicate exists in the array."""def find_min_rotate(array):    """    Finds the minimum element in a sorted array that has been rotated.    """    low = 0    high = len(array) - 1    while low < high:        mid = (low + high) // 2        if array[mid] > array[high]:            low = mid + 1        else:            high = mid     return array[low] def find_min_rotate_recur(array, low, high):    """    Finds the minimum element in a sorted array that has been rotated.    """    mid = (low + high) // 2    if mid == low:.

Assume nums is an array of integers that looks like this: -3 12 9 0 2 -1 If we are sorting from smallest to largest, what will nums look like after 2 times through the outside loop if we are using bubble sort? Note: When you're entering the values, make sure you leave at least one space between them. Would it be possible to perform a linear search on a 2-D array? Answers: Yes, but you would be limited to using only one loop No, because a 2-D array is not stored in linear fashion in RAM Yes, as long as you used the proper nested loops No, you would have to use a binary search Yes, but only if the array's elements were sorted

Two words (spelt in uppercase) are similar if and only if all letters in the 1st word are in the 2nd word and all letters in the 2nd word are in the 1st word; including the same number of duplications. For example, ABBA and BABA are similar; however, BABA and BAAA are not similar. To check two words which are similar, we can use two integer arrays, each has 26 elements (as we have 26 letters), you can assume that 1st array element stores the number of letter 'A', 2nd array element stores the number of letter 'B', and so on. What you need to do now is to check whether the two integer arrays are equal to decide whether the two words are similar. We propose following UML for this question: O TwoWords - String word1 -String word2 O Exam_Q4 +TwoWords0 - static Scanner input +TwoWords(String word1, String word2) O+TwoWords(TwoWords tw) O+ String getWord10 O+ static void main(String args) O+ String getWord20 O+void setinfo(String word1, String word2) O -intj countinfo (String word) O+boolean…