Given Information: Sample Size (n)= 115 Sample Mean (x) 10.8 Sample standard deviation (s) = 1.13 a. The population mean for the number of drugs prescribed to the patients is being estimated. b. The point estimate is the sample mean. In the given study, the sample mean () is 10.8. Thus, Point estimate = 10.8 c. The 98% confidence interval can be calculated by using the formula: CI=a/2n-1 X T Substitute the values in the above formula, and we get: CI= 10.840.02/2,114 X 1.13 VIIS The critical value of t can be calculated using the excel function =T.INV.2T(), Thus we have: =T.INV.2T(0.02,114) D C 2.3595 The 98% CI interval is, 1.13 CI= 10.8+2.3595 x V115 = 10.80.2486 = (10.80.2486, 10+ 0.2486) = (10.5514, 11.0486) Hence, the 98% confidence interval for u is (10.5514, 11.0486). The 80% confidence interval can be calculated by using the formula: CI=x+la/2n-1 X In Substitute the values in the above formula, and we get: 1.13 CI = 10.8 +40.20/2,114 XVII The critical value of t can be calculated using the excel function =T.INV.2T(), Thus we have: =T.INV.2T(0.2,114) D C 1.289 The 80% CI interval is, CI 10.8 1.289 x 13 VIIS = 10.80.1358 = (10.80.1358, 10+ 0. 1358) = (10.6642, 10.9358) Hence, the 80% confidence interval for u is (10. 6642, 10.9358).
Given Information: Sample Size (n)= 115 Sample Mean (x) 10.8 Sample standard deviation (s) = 1.13 a. The population mean for the number of drugs prescribed to the patients is being estimated. b. The point estimate is the sample mean. In the given study, the sample mean () is 10.8. Thus, Point estimate = 10.8 c. The 98% confidence interval can be calculated by using the formula: CI=a/2n-1 X T Substitute the values in the above formula, and we get: CI= 10.840.02/2,114 X 1.13 VIIS The critical value of t can be calculated using the excel function =T.INV.2T(), Thus we have: =T.INV.2T(0.02,114) D C 2.3595 The 98% CI interval is, 1.13 CI= 10.8+2.3595 x V115 = 10.80.2486 = (10.80.2486, 10+ 0.2486) = (10.5514, 11.0486) Hence, the 98% confidence interval for u is (10.5514, 11.0486). The 80% confidence interval can be calculated by using the formula: CI=x+la/2n-1 X In Substitute the values in the above formula, and we get: 1.13 CI = 10.8 +40.20/2,114 XVII The critical value of t can be calculated using the excel function =T.INV.2T(), Thus we have: =T.INV.2T(0.2,114) D C 1.289 The 80% CI interval is, CI 10.8 1.289 x 13 VIIS = 10.80.1358 = (10.80.1358, 10+ 0. 1358) = (10.6642, 10.9358) Hence, the 80% confidence interval for u is (10. 6642, 10.9358).
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 22PFA
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Transcribed Image Text:PLEASE INTERPRET A B AND C. THANK YOU
Given Information:
Sample Size (n) = 115
Sample Mean (x)= 10.8
Sample s tan dard deviation (s) = 1.13
a. The population mean for the number of drugs prescribed to the patients is being estimated.
b. The point estimate is the sample mean. In the given study, the sample mean () is 10.8. Thus,
Point estimate = 10.8
c. The 98% confidence interval can be calculated by using the formula:
CI= x ±la/2_n-1 X
n
Substitute the values in the above formula, and we get:
CI = 10.8 + 10.02/2,114 X 1.13
VIIS
The critical value of t can be calculated using the excel function =T.INV.2T(), Thus we have:
=T.INV.2T(0.02,114)
с
D
2.3595
The 98% CI interval is,
CI= 10.8+2.3595 x 1.13
VI15
= 10.8 +0.2486
= (10.80.2486, 10+ 0.2486)
= (10.5514, 11.0486)
Hence, the 98% confidence interval for uis (10.5514, 11.0486).
The 80% confidence interval can be calculated by using the formula:
CI= x ±lan-1 X
Substitute the values in the above formula, and we get:
CI= 10.8 +10.20/2,114
X
VIS
The critical value of t can be calculated using the excel function =T.INV.2T(), Thus we have:
=T.INV.2T(0.2,114)
D
C
1.289
The 80% CI interval is,
CI= 10.8 1.289 x 1.13
V115
= 10.8 +0.1358
= (10.8 -0.1358, 10+ 0.1358)
= (10.6642, 10. 9358)
Hence, the 80% confidence interval for u is (10.6642, 10.9358).
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