Given reaction rate data for: H2O2 + 31 + 2H* → I3 ¯ + 2H2O Trial [H2O2] M [1'] M [H'] M Rate (M/s) 1.15 x 106 2.30 x 106 2.30 x 106 1.15 x 106 0.010 0.020 0.010 0.010 0.020 1 0.00050 2 0.00050 0.010 0.010 3 0.00050 0.00100 4 0.010 Write the rate law for the reaction. O a. Rate = k[H2O2][I¯ ][H¯] O b. Rate = k[H2O2]²[I* ][H¯ ] O c. Rate = k[H2O2]²[I" ] O d. Rate = k[H2O2][I" ]?[H¯ ] O e. Rate = k[H2O2][I¯ ]

Chemistry by OpenStax (2015-05-04)
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Chapter12: Kinetics
Section: Chapter Questions
Problem 1E: What is the difference between average rate, initial rate, and instantaneous rate?
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Given reaction rate data for: H2O2 + 31" + 2H* → I3 ¯ + 2H2O
Trial
[H2O2] M
[1'] M
[H'] M
Rate (M/s)
1.15 х 10
2.30 x 106
2.30 x 106
1.15 x 106
1
0.010
0.020
0.010
0.010
0.020
0.010
0.00050
0.00050
0.00050
0.00100
3
4
0.010
0.010
Write the rate law for the reaction.
O a. Rate = k[H2O2][I¯ ][H¯ ]
O b. Rate = k[H202]²[I¯ ][H¯ ]
O c. Rate = k[H2O2]?[I" ]
O d. Rate = k[H2O2][I¯ ]?[H¯ ]
O e. Rate = k[H2O2][I¯ ]
Transcribed Image Text:Given reaction rate data for: H2O2 + 31" + 2H* → I3 ¯ + 2H2O Trial [H2O2] M [1'] M [H'] M Rate (M/s) 1.15 х 10 2.30 x 106 2.30 x 106 1.15 x 106 1 0.010 0.020 0.010 0.010 0.020 0.010 0.00050 0.00050 0.00050 0.00100 3 4 0.010 0.010 Write the rate law for the reaction. O a. Rate = k[H2O2][I¯ ][H¯ ] O b. Rate = k[H202]²[I¯ ][H¯ ] O c. Rate = k[H2O2]?[I" ] O d. Rate = k[H2O2][I¯ ]?[H¯ ] O e. Rate = k[H2O2][I¯ ]
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