Given that pKa for phenol is 9.95 and pKą for the ammonium ion is 9.24, will the following reaction be favorable? (Will the products be favored at equilibrium?) OH + NH3 phenol ammonia phenoxide ion ammonium ion pKa = 9.95 pKa = 9.24

Given that pKa for phenol is 9.95 and pKą for the ammonium ion is 9.24, will the following reaction be favorable? (Will the products be favored at equilibrium?) OH + NH3 phenol ammonia phenoxide ion ammonium ion pKa = 9.95 pKa = 9.24

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter4: Acids And Bases

Section: Chapter Questions

Problem 4.50AP: Write an equation for the acid-base reaction between 2,4-pentanedione and sodium ethoxide and...

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Question

Given that pKa for phenol is 9.95 and pKą for the ammonium ion is 9.24, will the following reaction be
favorable? (Will the products be favored at equilibrium?)
OH
+ NH3
phenol
pKa = 9.95
ammonia
phenoxide ion
ammonium ion
pKa = 9.24

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