Question
Asked Oct 31, 2019

Given that the ΔHorxn = -563.0 kJ, for the following reaction:

4FeO(s) + O2(g) → 2Fe2O3(s)

determine the standard enthalpy of formation, ΔHof, for: Fe2O3(s). Enter in kJ/mol.

check_circleExpert Solution
Step 1

Given that,

ΔΗ.
--563.0KJ
гxn
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ΔΗ. --563.0KJ гxn

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Step 2

The reaction is

4FeO(s)+0, (g)2Fe,0, (s)
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4FeO(s)+0, (g)2Fe,0, (s)

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Step 3

Now you calculate the enthalpy of...

2Fe,O, (s) -ΔΗ ,
κη
ΔΗ-5 63.0KJ
2Fe,Ο, (s)-5 63 .0K
-563.0KJ
Fe,0, (s)=
2
=-281.5KJ
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2Fe,O, (s) -ΔΗ , κη ΔΗ-5 63.0KJ 2Fe,Ο, (s)-5 63 .0K -563.0KJ Fe,0, (s)= 2 =-281.5KJ

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