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Given the following enthalpy values:                                                       Delta-Ho (kJ)             H2(g)  --> 2H(g)                       436             N2(g)  --> 2N(g)                       941             NH(g)  --> N(g) + H(g)              390          Calculate the enthalpy change (in kJ) for the reaction: N2(g) + 3H2(g) --? 2NH3(g)              (A) -91          (B) -597          (C) 91          (D) 597

Given the following enthalpy values:                                                       Delta-Ho (kJ)             H2(g)  --> 2H(g)                       436             N2(g)  --> 2N(g)                       941             NH(g)  --> N(g) + H(g)              390          Calculate the enthalpy change (in kJ) for the reaction: N2(g) + 3H2(g) --? 2NH3(g)              (A) -91          (B) -597          (C) 91          (D) 597

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.34QE
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  1. Given the following enthalpy values:

                                                      Delta-Ho (kJ)

            H2(g)  --> 2H(g)                       436

            N2(g)  --> 2N(g)                       941

            NH(g)  --> N(g) + H(g)              390

         Calculate the enthalpy change (in kJ) for the reaction:

N2(g) + 3H2(g) --? 2NH3(g)    

         (A) -91

         (B) -597

         (C) 91

         (D) 597

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