Given the following reactions: 2 NOCIE) → 2 NO + Cl2g) 2 NOe) + O2e) → 2 NO23 2 NO2 → N½O ArH = +75.56 kJ/mol ArH = -113.05 kJ/mol %3D ArH° = -58.03 kJ/mol Compute ArH° of N»O, - - Chu → 2 NOCI-O,, in kJ/mol.

Chemistry & Chemical Reactivity
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Chapter24: Biochemistry
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Given the following reactions:
ArH° = +75.56 kJ/mol
2 NOClg → 2 NO +
2 NOe + O2e) → 2 NO213)
2 NO212 → N2OalE)
ArH° = -113.05 kJ/mol
ArH° = -58.03 kJ/mol
Compute ArH° of N2O4g + Cl2g) → 2 NOCI + O2g in kJ/mol.
Transcribed Image Text:Given the following reactions: ArH° = +75.56 kJ/mol 2 NOClg → 2 NO + 2 NOe + O2e) → 2 NO213) 2 NO212 → N2OalE) ArH° = -113.05 kJ/mol ArH° = -58.03 kJ/mol Compute ArH° of N2O4g + Cl2g) → 2 NOCI + O2g in kJ/mol.
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