Given the thermochemical equations X2+3Y2⟶2XY3  ΔH1=−390 kJ X2+2Z2⟶2XZ2  ΔH2=−120 kJ 2Y2+Z2⟶2Y2Z   ΔH3=−230 kJ Calculate the change in enthalpy for the reaction. 4XY3+7Z2⟶6Y2Z+4XZ2

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
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Chapter4: Energy And Chemical Reactions
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Given the thermochemical equations

X2+3Y2⟶2XYΔH1=−390 kJ

X2+2Z2⟶2XZΔH2=−120 kJ

2Y2+Z2⟶2Y2Z   ΔH3=−230 kJ

Calculate the change in enthalpy for the reaction.

4XY3+7Z2⟶6Y2Z+4XZ2

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