h) Looking at the molecular groups for AXs and AX6 in the table on page 3, it can be determined that the order of magnitude for EG repulsion is: LP/BP = BP/BP > LP/LP BP/BP >> LP/BP > LP/LP LP/BP > BP/BP >> LP/LP i. %3D ii. iii. LP/LP >>> LP/BP > BP/BP LP/LP = LP/BP = BP/BP iv. V.
h) Looking at the molecular groups for AXs and AX6 in the table on page 3, it can be determined that the order of magnitude for EG repulsion is: LP/BP = BP/BP > LP/LP BP/BP >> LP/BP > LP/LP LP/BP > BP/BP >> LP/LP i. %3D ii. iii. LP/LP >>> LP/BP > BP/BP LP/LP = LP/BP = BP/BP iv. V.
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter4: Polar Bonds, Polar Reactions
Section: Chapter Questions
Problem 27E
Related questions
Question
![The actual structure of SF4 places the lone pair in only one of two possible sites. To discuss the
stability of the observed structures, we need only consider bond angles <120°. Repulsion effects
at angles 2120° are generally ignored. Consider the structure below.
axial
e) If the LP goes into the equatorial position labelled A, there will be
[2/3/4]x 90° angles between the LP and each BP.
OB
equatorial
f) If the LP goes into the axial position labelled B, there will be
[2/314]x 90° angles between the LP and each BP.
equatorial
axial
g) Considering your answers given in e) and f) above.
The most stable arrangement of EGs in SF4 places the LP in the [ axial / equatorial ]
position.
h) Looking at the molecular groups for AXs and AX6 in the table on page 3, it can be
determined that the order of magnitude for EG repulsion is:
i.
LP/BP = BP/BP > LP/LP
ii.
BP/BP >> LP/BP > LP/LP
LP/BP > BP/BP >> LP/LP
LP/LP >>> LP/BP > BP/BP
LP/LP = LP/BP = BP/BP
ii.
iv.
V.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F655bd7d6-0468-4553-bb81-2f5d532a8e20%2F2f352414-7136-49d6-8dfc-e581b94dc6d2%2Fj00qjhv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The actual structure of SF4 places the lone pair in only one of two possible sites. To discuss the
stability of the observed structures, we need only consider bond angles <120°. Repulsion effects
at angles 2120° are generally ignored. Consider the structure below.
axial
e) If the LP goes into the equatorial position labelled A, there will be
[2/3/4]x 90° angles between the LP and each BP.
OB
equatorial
f) If the LP goes into the axial position labelled B, there will be
[2/314]x 90° angles between the LP and each BP.
equatorial
axial
g) Considering your answers given in e) and f) above.
The most stable arrangement of EGs in SF4 places the LP in the [ axial / equatorial ]
position.
h) Looking at the molecular groups for AXs and AX6 in the table on page 3, it can be
determined that the order of magnitude for EG repulsion is:
i.
LP/BP = BP/BP > LP/LP
ii.
BP/BP >> LP/BP > LP/LP
LP/BP > BP/BP >> LP/LP
LP/LP >>> LP/BP > BP/BP
LP/LP = LP/BP = BP/BP
ii.
iv.
V.
Expert Solution
Step 1
h)
The given options are,
Step 2
Step by step
Solved in 3 steps with 3 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:
9780618974122
Author:
Andrei Straumanis
Publisher:
Cengage Learning
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:
9780618974122
Author:
Andrei Straumanis
Publisher:
Cengage Learning