The performance of students at a local community was recorded and categorized based on student’s faculty. The gathered data was then analyzed by a statistician and the results obtained using MINITAB are shown below:Expected counts are printed below observed counts. LowAverageHighTotalScience12(15.67)30(29.24)52(49.09)94engineer 14(10.67)20(19.91)30(33.42)**law4 (*)6(6.84)12(11.49)22Total30 5694180Chi - sq = 0.858 + 0.020 + *** + 1.042 0.000 + 0.350 + 0.030 + 0.104 + 0.023 = 2.600i. What is the degree of freedom for this test? ii. Estimate the p-value for this test. iii. State the conclusion for the test. Give a reason for your answer.

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Description: The performance of students at a local community was recorded and categorized based on student’s faculty. The gathered data was then analyzed by a statistician and the results obtained using MINITAB are shown below:Expected counts are printed below o

i) Degrees of freedom: df=(number of rows-1)(number of columns-1)=(3-1)*(3-1)=4 ii) p-value: The…

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Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.6: Summarizing Categorical Data

Problem 30PPS

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The performance of students at a local community was recorded and categorized based on student’s faculty. The gathered data was then analyzed by a statistician and the results obtained using MINITAB are shown below:

Expected counts are printed below observed counts.

	Low	Average	High	Total
Science	12 (15.67)	30 (29.24)	52 (49.09)	94
engineer	14 (10.67)	20 (19.91)	30 (33.42)	**
law	4 (*)	6 (6.84)	12 (11.49)	22
Total	30	56	94	180

Chi - sq = 0.858 + 0.020 + *** +

1.042 0.000 + 0.350 +

0.030 + 0.104 + 0.023 = 2.600

i. What is the degree of freedom for this test?
ii. Estimate the p-value for this test.
iii. State the conclusion for the test. Give a reason for your answer.

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