Health Care Public Option: A poll was conducted in 2009 in order to evaluate support for the healht carepublic option plan. 74% of 826 Democrats and 41% of 763 Independents support the public option.a) Calculate a 95% confidence interval for the difference between (Pp - Pi) and interpret it in this context.Assume all the conditions are met. Round your answers to the nearest percent.The confidence interval is: (%,%) Interpret the confidence

Givenp1^=0.74sample size(n1)=826p2^=0.41sample size(n2)=763confidence interval = 95%

Answered: Health Care Public Option: A poll was…

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter8: Sequences, Series, And Probability

Section8.7: Probability

Problem 6E: List the sample space of each experiment. Tossing three coins

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Similar questions

What is meant by the sample space of an experiment?
List the sample space of each experiment. Tossing three coins
In a past presidential election, 37,979,113 people voted for Candidate A 37,758,117 for Candidate B; and 206,521 for third-party candidates. a. What percentage of voters chose Candidate A? b. Would it be appropriate to find a confidence interval of voters choosing Candidate A? Why or why not?
A poll asked adults in a certain country whether immigration was a good thing or a bad thing for the country. Out of 1066respondents, 670 said it was a good thing. a. What percentage of those taking the poll said immigration was a good thing? b. Check the conditions to determine whether you can apply the CLT to find a confidence interval. c. Find a 95% confidence interval for the proportion who believe immigration is a good thing.
A poll asked adults in a certain country whether immigration was a good thing or a bad thing for the country. Out of 1032 respondents, 549 said it was a good thing. a. What percentage of those taking the poll said immigration was a good thing? b. Check the conditions to determine whether you can apply the CLT to find a confidence interval. c. Find a 95% confidence interval for the proportion who believe immigration is a good thing.
A computer store near campus is stocking its shelves and wants to know the relative proportions of USC undergraduates who use PCs vs Macs. A random sample of 60 USC undergraduates is surveyed, and each student is asked whether they use a PC or Mac more often. 55% select ”PC.” (a) What is the population and what is the sample in this study? (b) Calculate a 95% confidence interval for the proportion of USC students that are PC users. (c) Provide an interpretation of this confidence interval in the context of this problem.
Drinking A national health organization, concerned about drinking in middle school students, surveyed 220 randomly selected US 8th-grade students and found that 18 of them had had a drink of alcohol in the past month.(a) Find and interpret a 95% confidence interval for the proportion p of US 8th-grade students who drink alcohol.(b) Give the best estimate for p and give the margin of error for the estimate.
The business college computing center wants to determine the proportion of business students who have personal computers (PC's) at home, because if the proportion exceeds 25%, then the lab will scale back a proposed enlargement of its facilities. Suppose 300 business students were randomly sampled and 65 have PC's at home. Should they use a hypothesis test or a confidence interval to answer this question? a) Hypothesis test. b) Confidence interval.
A high school counselor is interested in determining factors that contribute to high school drop out rates. One factor of interest to her is whether kids who are involved in team sports as children are less likely to drop out of high school. She surveys 41 high school graduates and finds that 30 were involved in team sports as children. She then surveys 38 high school dropouts and finds that 23 were involved in team sports as children. Construct and interpret a 90% confidence interval for the true difference between the proportions of high school graduates and dropouts who participated in team sports as children. Does this data suggest that there is a difference between these proportions at this level of confidence? Correctly round your results to the nearest tenth of a percent (one decimal place) in the intepretation of your interval.
In a survey of 500 students, 180 students said that they prefer classes on Mondays and Wednesdays rather than on Tuesdays and Thursdays. Using a 95% confidence interval, answer the following questions. a. What is the margin of error for this study? b. Construct a 95% confidence interval that estimates the proportion of students that prefer classes on Mondays and Wednesdays.
The International Nanny Association (INA) reports that in a sample of 928 in- home child care providers (nannies), 128 have passed the INA Nanny Credential Exam (2014 International Nanny Association Salary and Benefits Survey). A. Use Wilson’s adjustment to find a 95% confidence interval for the true proportion of all nannies who have passed the INA certification exam. B. We want to decide whether the proportion of who passed the INA certification exam exceeds than .12 answer both a and b.

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