HERMODYNAMICCS: Given the following hypothetical thermochemical equations: AH = -1049.3 kJ AH = -1500.6 kJ 2QJ3 (g) + 3Q2X (g) → 4Q2 (g) + 3J2X (1) 4QJ3 (g) + 3X2 (g) – 2Q2 (g) + 6J2X (1) Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g) - Q2X (g) (Round off final answer to ONE decimal place)

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HERMODYNAMICS: Given the following hypothetical
thermochemical equations:
AH = -1049.3 kJ
AH = -1500.6 kJ
2QJ3 (g) + 3Q2X (g) → 4Q2 (g) + 3J2X (1)
4QJ3 (g) + 3X2 (g) –→ 2Q2 (g) + 6J2X (1)
Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g)
- Q2X (g)
(Round off final answer to ONE decimal place)
Round your answer to 1 decimal place.
Transcribed Image Text:HERMODYNAMICS: Given the following hypothetical thermochemical equations: AH = -1049.3 kJ AH = -1500.6 kJ 2QJ3 (g) + 3Q2X (g) → 4Q2 (g) + 3J2X (1) 4QJ3 (g) + 3X2 (g) –→ 2Q2 (g) + 6J2X (1) Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g) - Q2X (g) (Round off final answer to ONE decimal place) Round your answer to 1 decimal place.
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