Heroin, a tertiary amine, is a weak base because it contains a nitrogen atom with a lone pair of electrons. Therefore, it can be titrated with a mineral acid, e.g., HCI. Heroin has a molecular mass equal to 369.4176 g/mol. The crime laboratory took 75.000 mg of the mysterious white powder and dissolved it in one hundred mL of water. The resulting aqueous solution was titrated to the equivalence point with 5.000 mL of 0.02500 M HCI solution. Using these data, the percentages of heroin in the sugar/heroin mixture is O 30.12% O 21.90% 43.80% O 60.24%

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A mysterious white powder is found at a crime scene. A simple chemical analysis
concludes that the powder is a mixture of sucrose and heroin (I).
I
Transcribed Image Text:A mysterious white powder is found at a crime scene. A simple chemical analysis concludes that the powder is a mixture of sucrose and heroin (I). I
Heroin, a tertiary amine, is a weak base because it contains a nitrogen atom with a
lone pair of electrons. Therefore, it can be titrated with a mineral acid, e.g., HCI.
Heroin has a molecular mass equal to 369.4176 g/mol.
The crime laboratory took 75.000 mg of the mysterious white powder and
dissolved it in one hundred mL of water. The resulting aqueous solution was
titrated to the equivalence point with 5.000 mL of 0.02500 M HCl solution.
Using these data, the percentages of heroin in the sugar/heroin mixture is
O 30.12%
O 21.90%
O 43.80%
O 60.24%
Transcribed Image Text:Heroin, a tertiary amine, is a weak base because it contains a nitrogen atom with a lone pair of electrons. Therefore, it can be titrated with a mineral acid, e.g., HCI. Heroin has a molecular mass equal to 369.4176 g/mol. The crime laboratory took 75.000 mg of the mysterious white powder and dissolved it in one hundred mL of water. The resulting aqueous solution was titrated to the equivalence point with 5.000 mL of 0.02500 M HCl solution. Using these data, the percentages of heroin in the sugar/heroin mixture is O 30.12% O 21.90% O 43.80% O 60.24%
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