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- The forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β=15° with the horizontal axis. Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=20 cm, b =33 cm and c= 65 cm, respectively. The athlete's hand is exerted by a force of F= 150 N, which makes an angle of γ=30° with the vertical from the point C. The weight of the athlete's arm is W= 100 N. The direction of application of the Fm muscle force makes an angle of α=25° with the longitudinal axis of the arm. According to this; a) Calculate the FM muscle strength. b) Calculate the angle θ of the FJ joint reaction force with the horizontal.…1.For Figure Q1a, at what angle θ must the force F2 (= 1240 N) be applied in order that the resultant force R of the two forces F1 and F2 has a magnitude of 3100 N? Give your answer in degrees to 2 decimal places. 2. For Figure Q1a, what is the angle between the resultant force R (=3100 N) and the y-axis.Give your answer in degrees to 2 decimal places. 3. The pulley system shown in Figure Q1 clifts a mass,m,of 550kg.Calculate the force FA necessary to maintain the suspended mass in static equilibrium; and determine the forces at the ceiling anchor points A and B. Assume frictionless and weightless pulleys and use g = 9.81 m/s2.The rectangular framework is subjected to the following non-concurrent system of forces: a 30lb- force below the origin, a 20 lb-force,3ft above the origin and making an angle of30°N of E, a 100lb-force with a horizontal distance of 3ft and a vertical distance of 4ftfrom the origin and making an angle of 45°NW , a 60lb -force with the same distance like the previous force but along the positive x-axis, and a 100lb- force 4ft tothe right of the origin and making an angle of 60° S of W . Determine the magnitude and direction of the resultant, as well as its moment arm relative to the origin.
- simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. θ1 = 35 degree and θ2 = θ3 = 20 degree. Calculate the moment that the force, F, exerts about the point A. *The square in the figure below is being rotated about the point P by 5 forces of the same magnitude. Rank the torque exerted by each force greatest to least. Separate values with a space or comma and enter subscripts as regular numbers ( F5 F4). If two torques are equal you can enter either first.Consider Figure 5.28. The driver attempts to get thecar out of the mud by exerting a perpendicular force of610.0 N, and the distance she pushes in the middle of therope is 1.00 m while she stands 6.00 m away from the caron the left and 6.00 m away from the tree on the right.What is the tension T in the rope, and how do you find theanswer?
- The sketch shows the top view of a door that has width, L. The small blue circle is hinge. The door is free to rotate about the hinge. All forces have same value, F. The angled forces and F5 are at the middle of the L. (a) Draw the line of action of force for each force on the given diagram. (b) Draw the lever force of each forces shown above. There should be a drawing for each force including the force, its line of action, axis of rotation and finally the lever arm. (c) Write down the torque due to each force using sign convention used in class. Label a force first and then write the torque equation.Consider the frame shown in (Figure 1). Suppose that w = 5.5 kN/m Determine the x and y components of force that pin A exert on the frame using scalar notation. Determine the x and y components of force that pin B exert on the frame using scalar notation.The drawing shows a rectangular piece of wood. The forces applied to corners B and D have the same magnitude of 20 N and are directed parallel to the long and short sides of the rectangle. The long side of the rectangle is twice as long as the short side. An axis of rotation is shown perpendicular to the plane of the rectangle at its center. A third force (not shown in the drawing) is applied to corner A, directed along the short side of the rectangle (either toward B or away from B), such that the piece of wood is at equilibrium. Find the magnitude and direction of the force applied to corner A.
- 1. Find the sum of the horizontal forces of a non-concurrent force system as shown in figure 1. NOTE: Choose the nearest value/option. 2. Find the sum of moments about the origin (or at point O) of a non-concurrent force system as shown in figure 1. NOTE: 1. point O is the intersection of the x-axis and the y-axis; 2. take counterclockwise moment as (+) moment; 3. choose the nearest value/option.Question 1) The forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β=25° with the horizontal axis. Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=20 cm, b=30 cm and c= 62 cm, respectively. A force of F= 130 N, which makes an angle of γ=30° with the vertical from the point C, acts on the athlete's hand. The weight of the athlete's arm is W= 85 N. The direction of application of the Fm muscle force makes an angle of α=20° with the longitudinal axis of the arm. According to this; a) Calculate the FM muscle strength b) Calculate the angle θ of the FJ joint reaction force with the…A: Moment arm of the force In the figure, the dashed line extending from the force vector F is called the line of action of F. The force’s moment arm is the perpendicular distance rm from the pivot point P to the line of action. What is rm, the length of the moment arm of the force F about point P? Express your answer in terms of r and θ. Find the moment M about P due to F. Your answer should correctly express both the magnitude and the sign of M. Express your answer in terms of either rm and F or r, θ, and F. B: As shown (Figure 2), resolve the force vector, F, into radial (parallel to r) and tangential (perpendicular to r) components. Find the magnitude of the radial and tangential components, Fr and Ft. Assume that θis between zero and 90 degrees. Express your answers in terms of F and θ Is the following statement true or false? The moment about point…