How do you derive the numbers .99928 and .9943 in part d of this question. I only need help with part d.Thank you. (USL- LSL)C,,=60(46- 36)6(1.5785)109.4711.055Hence, process capability i.e. C, is 1.055(d)percentage of rework = Pr{x>USL}46-40)=1-0{1.5785=1-0{3.8010}=1-0.999280.00072percentage of scrap = Pr {x < LSL}(40-36=1-01.5785=1-¢{2.5340}=1-0.9943= |0.0057Hence, the percentage of rework producing is 0.072% and the percentage of scrap producing is0.57 %.

The mean and standard deviation of standard normal distribution are 0 and 1, respectively.

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How do you derive the numbers .99928 and .9943 in part d of this question. I only need help with part d.

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter4: Eigenvalues And Eigenvectors

Section4.6: Applications And The Perron-frobenius Theorem

Problem 25EQ

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