Q: 100.0 mL of a 0.580 M solution of KBr is diluted to 500.0 mL. What is the new concentration of the…
A: Given that, 100 mL of 0.580 (M) solution of KBr is diluted to 500 mL We know that, V1S1 = V2S2…
Q: 3. Determine the normality of 3200mL HCI if 25.27g of acid was used.
A:
Q: ilculate the hydroxide ion concentrati .0100 M sodium hypochlorite solutio .33x10-7 5.8x10-5 8x10-4
A:
Q: Cl2 and 0.020 M M9CI2, which of the following
A:
Q: The (-log[H^ + ]) of a solution is 4.16, The [H^ + ] is? using proper significant figures
A: We take same number of significant figures in Concentration term as there are sig figs after decimal…
Q: Q1/ The molarity and Normality for 250 ml of ?1.05% NaHCO3
A: Molarity is defined as the number of moles of solute dissolved in 1 litre of solution. where a…
Q: PPM
A: The correct answer about NMR spectrum is given below
Q: Tom, an analytical chemist, bought a bag of decaffeinated coffee from a grocery store. However, Tom…
A: Solution - According to the question - Given - C1*V1 = C2*V2 Dilution law - Ostwald's dilution law…
Q: What is the process by which sediment comes to rest
A:
Q: A student prepares a 0.28 mM aqueous solution of propionic acid (C₂H₂CO₂H). Calculate the fraction…
A: Propionic acid is a weak acid. It doesn't completely dissociate in an aqueous solution to form…
Q: 100.0 mL of a 0.890 M solution of KBr is diluted to 500.0mL. what is the new concentration of the…
A:
Q: ume of acid (V) = ml. Volume of base () = ml.
A: We have to find the volume of acid and volume of base, to make given buffer Given pH = 9.24 pKa =…
Q: please highlight the correct answer
A: Hello. Since you have posted multiple questions and not specified which question needs to be solved,…
Q: You have a solution that is 1.5 M 100.0 mL of 0.18 M ? How many milliliters of this acid do you need…
A:
Q: if 400mL of a 2M saltwater solution is mixed with 550mL of a 6M saltwater solution, what is the new…
A:
Q: if you want to make 1000.0 mL of a 0.150 M solution starting with a standard solution of 0.550 M,…
A:
Q: 100.0 mL of a 0.550 M solution of KBr is diluted to 500.0 mL. What is the new concentration of the…
A:
Q: If the initial recorded volume titrated is 0.50 ml and the final recording is 26.95 ml, what is the…
A:
Q: Use only 1 decimal point (X.X) for all atomic weights. What will be the final molarity of 5.00 mL of…
A: Given :M1 = molarity of Nitric acid initially = 14 MV1 = Initial volume of Nitric acid = 5 m…
Q: Complete the table. That is, fill in any missing entries in the second and third columns. Round your…
A: The question is based on the concept of PH and pOH calculations. pH is defined as negative…
Q: Calculating 12.49 mg. KI in 104.5mL of solution
A: Molarity is the ratio of moles of solute to volume of solution in litres. Molarity=no. of moles of…
Q: Calculate the equivalent weight and normality for a solution of 6.0 M H3PO4 given the following…
A: Given, H3PO4 (aq) + 3OH- (aq) ------------> PO43- (aq) + 3H2O (l) Molarity of H3PO4 = 6 M…
Q: Gastric acid pH can range from 1 to 4, and most of the acid is HClHCl. For a sample of stomach acid…
A:
Q: 1. A process of determining the volume of an acid which is equivalent to a known weight of a pure…
A: To write one word for the following given sentences:
Q: An 2000mL of 5% solution is to infuse at 250mL per hour. What is the infusion time in minutes? Round…
A: Infusion rate is the passage of volume of solution per unit time.
Q: A 23.74-mL volume of 0.0981 M NaOH was used to titrate 25.0 mL of a weak monoprotic acid solution to…
A: Since , the acid is monoprotic then we can use this formula M1V1 = M2V2 to…
Q: An aqueous solution is made of the diprotic acid H2A to a concentration of 0.15 M H2A. Ka1 = 3.0 x…
A:
Q: 100.0 ml of a0.500 M solution of KBr is diluted to 500.0 ml, what is the new concentration?
A: Determining new concentration.
Q: H.W: 1- A solution of KCI (its volume 500 mL) contains 7.45 ppm KCI. Calculate its Molarity and…
A: Given, Volume of solution = 500 ml =0.50 L ppm concentration of KCl = 7.45 ppm Molar mass of KCl =…
Q: 2. Calculate the [I] (after dilution in the 50.00 mL flasks) for the four standard solutions you…
A: With dilution concentration of a substance decreases.
Q: A student determined that it took 5.65 mL of NBS to reach an endpoint with a standard solution that…
A: To calculate Concentration of vitamin C in orange juice sample , we can use relation M1 / V1 = M2 /…
Q: A 4.0 MG/dL standard solution is needed. To prepare is 100ML of the working standards, how much…
A: Given, A 4.0 mg/dL standard solution is needed. To prepare is 100 mL of the working standards, the…
Q: Calculate the molarity of 1 Lof water at 20°C given a density of 0.9982 g/mL. Select an answer and…
A: To solve this problem first we calculate the mass of water using its density and volume . Then we…
Q: The solubility of CACO, in water at 25 °C is measured to be 0.0067 . Use this information to…
A: The concentration of the calcium chloride in the solution is = 0.0067 g/L The value of the…
Q: A chemist wants to make a 40% acid solution. He has 20 mL of a 75% acid solution. How many mL of…
A: Answer : Goal we have to prepare 40% acidic solution Amount of acid =40/100…
Q: .. A solution of NaOH has a oxalic acid (MW 126.0) titer of 9.45 mg/mL. Calculate the normality of…
A: Quatity of Oxalic acid = 9.45 mg/mL We know that., 1 mg/mL = 1 g/L Therefore., Quatity of Oxalic…
Q: Hi, A 0.750 gram samples of sodium carbonate required 35.8 mL of a sulfuric acid solution complete…
A:
Q: Q4/B-I have 0.749 g/ mL and I want to use this concentration to calculate the grams of aspirin in…
A: Density =0.749g/ml Volume=100mL
Q: Only 100grams of sugar will dissolve in 500mL of water at room temperature. If I want to make rock…
A: Supersaturated solution.
Q: 100.0 mL of 2.500 M KBr solution is on hand. You need 0.5500 M. What is the final volume of solution…
A: The question is based on the concept of solutions. we have been given stock solution. we need to…
Q: What does this graph show? -273 K 0 1000 1273 K -2273 K 2000 € 3000
A: Maxwell Boltzmann equation is an equation which forms the basis of the kinetic theory of gases. This…
Q: What is the weight (in grams) to prepare a 350 mL of 0.047 M solution? * (Encode the complete…
A:
Q: 4. A 500-mL graduated flask contains 150 mL of 0.200 N H2SO4. By adding a more concentrated H2SO4,…
A:
Q: Find the normality of a KOH solution if 27ml of 2.2N HCI solution is neutralized by 21ml of KOH…
A:
Q: normality of 0.5781 g acid (eq wt = 187.3) in 250.0 mL of solution
A:
Q: if 0.5 ml of blood is added to 9.5ml of saline, what is the dilution
A: Given: Volume of blood = 0.5 mL Volume of saline = 9.5 mL
Q: How many milliliters of 11.5 M HCI(aq) are needed to prepare 255.0 mL of 1.00 M HCI(aq)? V = mL -…
A:
![+ kt
[N2O],
t = 1250 seconds
%3D
%3D
20], = 0.108 M
k = 1.10×10-3 M-'s
%3D
1
+ (1.10×10-3 M's)(1250 s
1
%3D
N20],
0.108 M
1
10.6 M-1
%3D
[N2O],
[N2O],
0.0940 M
Use Integrated Rate Law to Calculate Reactant
Concentration at Time t
sition of nitrous oxide at 565 °C
N2(g) + 2 O2(g)
er in N20 with a rate constant of 1.10 x 10-3 M-1s1.
ent is performed where the initial concentration of
M, what is the N,0 concentration after 1250](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2e59b0f6-3039-46d3-a26b-d87030adb520%2F58eec14b-84dd-4d7b-a0c1-27f1185ccd4e%2F6g8vhy4_processed.jpeg&w=3840&q=75)
Step by step
Solved in 2 steps with 2 images
- There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…4. Ksp=4.1x10-36 for Pb3(AsO4)2Calculate Eofor Pb3(AsO4)2(s) + 6e- 3Pb(s) + 2AsO43-Pb2+ +2e- Pb(s) Eo= -0.126 V
- (asap plzz 10 minAn exothermic reaction is taking place in a constant volume reactor that contains a cooling coil. The reaction A -> B proceeds with a reaction rate constant of k1. The rate of reaction is given as kCA. The feed concentration of A is 4 mol/L, the reaction conversion is 50%, and the reaction rate constant k is 1*10-2 h^-1. The volumetric flow rate remains constant throughout the reaction, at 2 L/hr. The initial temperature in the reactor is 40°C, and the final temperature is 60°C. The heat released at the end of the reaction is 60 j/mol. The amount of heat removed by the coil is 400 j. The density of the mixture is 4 kg/m^3, the Cp value is 20 j/mol.K. If the reactor volume is 4 liters, find the change in temperature over time.Show all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdk
- calculate the flow rate in ml/hr . order 40meq/l at 10meq/hr in 1000ml in d5w supply 20meq/10mlQ27 A 10-1 is performed on a culture of bacteria in order to perform viable plate counts. From the dilution, *0.1 mL* of solution is plated on solid media, and 265 colonies of bacteria grow on the plate. Assuming each colony came from a single bacterium, how many bacteria are in a single mL of the original culture? Express your answer as a whole number. Since only 0.1 mL is put on the plate, this counts as an extra dilution!!! Any time less than 1 mL is transfered, a dilution is being performed. Any time more than 1 mL is transfered, a concentration is being performed.Consider the following data on the hypothetical reaction 2A + 2B C + 3D between reactants A and B togive products:Sl No. [A] (mold m-3) [B] (mold m-3) Rate, r (mold m-3s-1)i 6.0 × 10-3 1.0 × 10-3 0.012ii 6.0 × 10-3 2.0 × 10-3 0.024iii 2.0 × 10-3 1.5 × 10-3 0.002iv 4.0 × 10-3 1.5 × 10-3 0.008If the reaction rate is given by r = [A]a[B]b, then (i) what is the order of the reaction with respect to A? (ii)what is the order of the reaction with respect to B? (iii) what is the overall order? (iv) Write the rate lawequation. (v) Calculate the rate constant.
- You are trying to come up with a drug to inhibit the activity of an enzyme thought to have a role in liver disease. In the laboratory the enzyme was shown to have a Km of 1.0 x 10-6 M and Vmax of 0.1 micromoles/min.mg measured at room temperature. You developed an uncompetitive inhibitor. In the presence of 5.0 x 10-5 M inhibitor, the apparent Vmax was determined to be 0.02 micromoles/min.mg. What is the Ki of the inhibitor?You are trying to come up with a drug to inhibit the activity of an enzyme thought to have a role in liver disease. In the laboratory the enzyme was shown to have a Km of 1.0 x 10-6 M and Vmax of 0.1 micromoles/min.mg measured at room temperature. You developed a competitive inhibitor. In the presence of 5.0 x 10-5 M inhibitor, the apparent Km of the enzyme was found to be 1.5 x 10-5 M. What is the Ki of the inhibitor?( dint answer afrr 10.10 asap