How many bytes are required to store the variables declared in the following C language code: void main(void){ // void is required since this is an embedded system char sample_nc; // character requires one byte int sample_ng; // integer requires two bytes struct { char name[10] ; int q_grade[5]; } test[4];
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- translate the c++ code into pep/9 assembly language #include <iosream> using namespace std; void minimum (int i1, int i2){ if (i1 < i2) cout << i1 << " is less than " << i2 << endl; else if (i1 > i2) cout << i2 << " is less than " << i1 << endl; else cout << i1 << " equals " << i2 << endl;}int main (){ int n, m; cout << "Enter two integers: "; cin >> n >> m; minimum (n, m); return 0;}please solve the problem using c language pointers please indicate the print and the intended output <stdio.h> int main(){} char letters[26]; char *pc1 = letters; /* Equivalent pointer values. */ char *pc2 = &letters; char *pc3 = &letters[0]; letters[4] = "e"; /* Equivalent indexes. */ pc1[4] = ’e’; *(letters + 4) = "e"; *(pc2 + 4) = "e"; pc3 = &letters[10]; /* Equivalent addresses. */ pc3 = &pc1[10]; pc3 = letters + 10; pc3 = pc2 + 10; }Please send me answer within 10 min!! i will rate you good for sure!! Please provide explaination for your solution!! I need help programming this code in C++ ASSEMBLY LANGUAGE. I need help ASAP. Thank you. By Assembly Language, I mean this following format: #include <iostream> using namespace std; //any voids void ...() { } // any varibles int/short variable_n int main () { _asm { ... Assembly Code } } I must use the asm format above.
- Convert the following C++ programs into Pep/9 assembly language: void minimum (int i1, int i2) { if (i1 < i2) cout << i1 << " is less than " << i2 << endl; else if (i2 < i1) cout << i2 << " is less than " << i1 << endl; else cout << i1 << " equals " << i2 << endl; } int main () { int n, m; cout << "Enter two integers: "; cin >> n >> m; minimum (n, m); return 0; }In C++, please explain in detail Declare an integer variable XYZ and a pointer called XYZpointer. Write the C++ statemens that will correcty make pointer variable XYZpointer point to the storage location XYZ and extract its address.What are the advantages and disadvantages of using decimal data types?
- * Assignment: Word operations * * Description: * This assignment asks you to implement common word operations that are * not available in the Scala programming language. The intent is to practice * your skills at working with bits. * */ package wordOps /* * Task 1: Population count (number of 1-bits in a word) * * Complete the following function that takes as parameter * a 32-bit word, w, and returns __the number of 1-bits__ in w. * */ def popCount(w: Int): Int = ??? /* * Task 2: Reverse bit positions * * Complete the following function that takes as parameter * a 16-bit word, w, and returns a 16-bit word, r, such that * for every j=0,1,...,15, * the value of the bit at position j in r is equal to * the value of the bit at position 15-j in w. * */ def reverse(w: Short): Short = ??? /* * Task 3: Left rotation * * Complete the following function that takes two parameters * * 1) a 64-bit word, w, and *…Convert the following C++ program into an x86 assembly language program.Comment the start of each "code block" that performs one of the listed mathematical calculations.Comments go to the right of the actual code, all starting on the same column.Post ONLY your ASM file here to Blackboard when complete. // Global variablesint a = 5;int b = 6;int c = 7;int d = 8;int e = 2;int f = 3;int g = 1;int h = 4;// Codeint main(){ --g; b = f + h; e = d + 22 - c - a; f = -g; ++a; g = f + e - 5; a = d + 19 - b; h = c + a + (-f); // Move a into the eax register // Move b into the ebx register // Move c into the ecx register // Move d into the edx register // Call the DumpRegs function // Move e into the eax register // Move f into the ebx register // Move g into the ecx register // Move h into the edx register // Call the DumpRegs function g = g + 6; f = 16; --h; d = 5 - e; b = -b; e = -g + 11 - a; f = d + c - a; c…The following data structure is declared in a C/C++ program: struct DATA { int a; char b; short c; int d; char e; } Given: int = 4 bytes, char = 1 byte, short = 2 bytes, draw the most likely arrangement of data in memory for each of the following situations: a) On an Intel Architecture computer running the Linux OS b) On an Intel Architecture computer running the MS Windows OS c) On a computer that imposes 4-byte word alignment
- Please send me answer within 10 min!! I will rate you good for sure!! Please read the question carefully!! i am beginner of programming fundamental. so each code of line comment and explanation. do not use this header files : #include<alogorithm>, #include<vector> console on output pic will be send Instructions: 1. You are not allowed to use anything other than pointers and dynamic memory. 2. One function should perform one functionality only. 3.code in C++.language Write a program in C++ language that dynamically allocates an array large enough to hold a user-defined number of test scores. Once all the scores are entered, the array should be passed to a function that sorts them in ascending order. Another function should be called that calculates the average score. The program should display the sorted list of scores and averages with appropriate headings. Use pointer notation rather than array notation whenever possible. Input Validation: Do not accept negative numbers…Question 3 Please write a program in Assembly Write a data-only program to define: 1) an array of 10 8 byte integers initialized with 0-9 in the data segment 2)an array of five 2 byte integers initialized to 0 in the bss segment. Full explain this question and text typing work only thanksPlease write in Assembly x86 with console 32 to work in Visual Studio 2022 Please provide the proper directives and no Error A2034: must be in segment block 3. Create an 80x86 program that define an array of doubleword numbers then read two values, first one indicates how many actual numbers will be in the array, and an integer n. The program should display all of the numbers in the array that are greater than the number n..586 .MODEL FLAT .STACK 4096 .DATA directives number DWORD -105 sum DWORD 2 .CODE reserve 4096-byte stack ; reserve storage for data ; start of main p rogram code main PROC