How many moles of Agl will be formed when 75.0 mL of 0.300 M AGNO3 is completely reacted according to the balanced chemical reaction: 2 AGNO3(aq) + Cal2(aq) → 2 Agl(s) + Ca(NO3)2(aq)

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Q: How many moles of Agl will be formed when 75.0 mL of 0.300 M AgNO3 is completely reacted according…

A: The question is about calculating the Number of Moles of AgI that will be formed when 75.0 mL of…

Q: How many grams of AgCI will be formed when 60.0 mL of 0.500 M AGNO; is completely reacted according…

A: Given values are-> Volume of AgNO3 = 60.0ml =60.0 × 10^-3litere=0.060 l Molarity = 0.500M

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Q: How many moles of Agl will be formed when 75.0 mL of 0.300 M AGNO3 is completely reacted according…

A: SOLUTION: Step 1: The number of moles of AgNO3 is calculated from the below equation.…

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Q: How many grams of AgCI will be formed when 60 mL of 0.500 M AGNO3 is completely reacted according to…

A: Given: Volume of AgNO3 = 60 mL = 0.06 L Amount of AgNO3 = 0.5 M From the balanced chemical equation…

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Q: How many moles of Agl will be formed when 75.0 ml of 0.300 M AGNO. is completely reacted according…

A: Interpretation: The moles of AgI will be formed when 75.0 mL of 0.300 M AgNO3 is completely reacted…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO₃)₂ reacts with 29.0 mL of…

A: [Cu(NO₃)₂] = 0.50 M VCu(NO₃)₂ = 20.5 ml  nCu(NO₃)₂ =  0.50 M x 20.5 ml = 10.25 m mol [NaOH ] = 0.50…

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".